Your answer is going to be fifteen plus r
<em>Answer:</em>
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We know that imaginary roots always come in pairs, so we already know 4 solutions
-2, 2, 4 + i and a pair of 4 + i
Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots
So for sure, we will have 3 real roots and 2 imaginary roots
Last option, f(x) has three real roots and two imaginary roots
4x^2 +15x + 13 tyats would be tour answrr
Do you mean 3y? If so, 3y = 1/2x + 2
3y - 1/2x = 2 is standard form