First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:

The figure would look kinda like this:
R
M
S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:

and

Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram
Answer:
There are two answers, either of which would work
- 26°, 26° and 128°
- 26°, 77° and 77°
Method:
An isosceles triangle has 2 of the same sides so there are two possible answers:
1) 26° is one of the angles which is the same as another. 26° × 2 = 52° and since there are 180° in a triangle the other angle is 180° - 52° which is 128°. This would make the angles 26°, 26° and 128°
2) 26° is not one of the angles which is the same as another. Since there are 180° in a triangle, the other angles would both be 2 ÷ (180° - 26°) which is 77°. This would make the angless 26°, 77° and 77°
Answer:
y=h(x)-8
Step-by-step explanation:
it shifted down 8 units
Step-by-step explanation:
<h2>sasuka:pire</h2><h3> 3:5</h3><h3>3/8:5/8=3/8×24×8/5 </h3>
= 14.4