True. I think.................
Cesium has the least ionization energy and can donate electrons very easily !
Answer:
The force of impact, F = 17682.18 N
Explanation:
Given,
The initial velocity of the truck and associated velocity of RV, u = 2 m/s
The height of the cliff, h = 280 ft
= 85.344 m
The mass of the RV, m = 1800 Kg
The total energy of the RV at height, 'h' with velocity, 'v', E = P.E + K.E
P.E = mgh J
= 1800 x 9.8 x 85.344
= 1505468.16 J
K.E = mv²/2
= 1800 x 2² / 2
=3600 J
Therefore total energy, E = 1509068.16 J
This is equal to the kinetic energy of RV at the impact.
The force of impact,
F = E/h
= 1509068.16 J / 85.344 m
= 17682.18 N
Hence, the force of impact of RV is, F = 17682.18 N
Answer:
2.7km
Explanation:
Two methods: Convert km/hour to km/minutes or convert 3/2 minutes to hours.
Then multiply time to get the distance of the car traveled.
To solve this problem we will apply the concept related to the balance of forces. Here the electrostatic force defined by Coulomb's laws must be proportional to the weight of the electron, defined by Newton's second law, so that such balance exists, both can be described as:
Here,
Charge required
Charge of electron
d = Distance
k = Coulomb's constant
= mg
Here,
m = mass
g = Gravitational acceleration
In equilibrium the sum of Force is zero, then,
Therefore the charge required for this to happen is 
