Answer:
A) P1=2 [bar] , W=-12 [kJ]
B) P1=0.8 [bar] , W=-7.3303 [kJ]
C) P1=0.6077 [bar] , W=-6.4091 [kJ]
Explanation:
First, from the problem we know the following information:
V1=0.1 m^3
V2=0.04 m^3
P2=2 bar =200 kPa
The relation PV^n=constant means PV^n is a constant through all the process, so we can derive the initial pressure as:
a) To the case a) the constant n is equal to 0, we can calculate the initial pressure substituting n=0 in the previous expression, so:
The expression to calculate the work is:
If n=0:
Then:
The work is:
b) To the case b) the constant n is equal to 1, we can calculate the initial pressure substituting n=1 in the initial expression, so:
If n=1 then:
To calculate the work:
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Substituting:
c) To the case c) the constant n is equal to 1.3, we can calculate the initial pressure substituting n=1.3 in the initial expression, so:
First:
The work:
Substituting:
W=-6.4091 kJ
Answer:
<h2>1.5 ohms</h2>
Explanation:
Power is expressed as P = V²/R
R = resistance
V = supplied voltage
Given P = 600W and V = 30V
R = V²/P
R = 30²/600
R = 900/600
R = 1.5ohms
magnitude of its resistance is 1.5ohms