Answer:
801.1 kJ
Explanation:
The ice increases in temperature from -20 °C to 0 °C and then melts at 0 °C.
The heat required to raise the ice to 0 °C is Q₁ = mc₁Δθ₁ where m = mass of ice = 1 kg, c₁ = specific heat capacity of ice = 2108 J/kg°C and Δθ₁ = temperature change. Q₁ = 1 kg × 2108 J/kg°C × (0 - (-20))°C = 2108 J/kg°C × 20 °C = 4216 J
The latent heat required to melt the ice is Q₂ = mL₁ where L₁ = specific latent heat of fusion of ice = 336000 J/kg. Q₁ = 1 kg × 336000 J/kg = 336000 J
The heat required to raise the water to 100 °C is Q₃ = mc₂Δθ₂ where m = mass of ice = 1 kg, c₂ = specific heat capacity of water = 4187 J/kg°C and Δθ₂ = temperature change. Q₃ = 1 kg × 4187 J/kg°C × (100 - 0)°C = 4187 J/kg°C × 100 °C = 418700 J
The latent heat required to convert the water to steam is Q₄ = mL₂ where L = specific latent heat of vapourisation of water = 2260 J/kg. Q₄ = 1 kg × 2260 J/kg = 2260 J
The heat required to raise the steam to 120 °C is Q₅ = mc₃Δθ₃ where m = mass of ice = 1 kg, c₃ = specific heat capacity of steam = 1996 J/kg°C and Δθ₃ = temperature change. Q₃ = 1 kg × 1996 J/kg°C × (120 - 100)°C = 1996 J/kg°C × 20 °C = 39920 J
The total amount of heat Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅ = 4216 J + 336000 J
+ 418700 J + 2260 J + 39920 J = 801096 J ≅ 801.1 kJ
Answer:
Y = 176.4 m
Explanation:
For the height of cliff we will analyze the vertical motion. We will apply the 2nd equation of motion:
Y = V₀y*t + (0.5)gt²
where,
Y = Height = ?
V₀y = Initial Vertical Velocity = 0 m/s (since, ball is thrown horizontally)
t = time = 6 s
g = 9.8 m/s²
Therefore,
Y = (0 m/s)(6 s) + (0.5)(9.8 m/s²)(6 s)²
<u>Y = 176.4 m</u>
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).
If we call

the speed of the primary waves and

the speed of the secondary waves, and we call

the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as


So the lag time between the arrival of the P-waves and of the S-waves is

We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
<span>In Coulomb's law, however, the
magnitude and sign of the electric force are determined by the electric
charge, rather than the mass, of an object. ... Thus, two negative
charges repel one another, while a positive charge attracts a negative
charge. The attraction or repulsion acts along the line between the two charges</span>