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Alexxandr [17]
3 years ago
7

A car has uniform velocity of 108km/hour. How far does it travel in 1 1/2 minutes

Physics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

2.7km

Explanation:

Two methods: Convert km/hour to km/minutes or convert 3/2 minutes to hours.

Then multiply time to get the distance of the car traveled.

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The density of an object is .835 g/cm3. If its volume is 34 cm3, what is the mass of the object?
zaharov [31]

D = m/v


Given:

D: .835 g/cm3

V: 34 cm3

M: ?


M= Dxv


M= .835 g/cm3 x 34 cm3

M= 28.39 g

4 0
3 years ago
Read 2 more answers
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Setler79 [48]
What you’re doing is so easy pay attention more I think
4 0
3 years ago
A science teacher tells her class that their final project requires students to measure a specific variable and determine the ve
iogann1982 [59]

Answer:

Yes

Explanation:

The velocity measured by Jennifer and Johnny is

v_m = 34.87 m/s

The actual velocity is

v=34.15 m/s

We can calculate the % error of the students measurement as follows:

Err = \frac{v_m - v}{v}\cdot 100 = \frac{34.87 m/s-34.15 m/s}{34.15 m/s}\cdot 100 =0.021 \cdot 100 = 2.1 \%

Which is lower than the 2.5% maximum error required, so the two students will pass the test.

4 0
3 years ago
Bonus: What is the velocity of an 8 kg lead shot-put if it has 484 J of energy? Type here to search e​
Dima020 [189]

Answer:

11m/s

Explanation:

Given parameters:

Mass of the lead shot = 8kg

Energy of the shot  = 484J

Unknown:

Velocity of the shot  = ?

Solution:

To solve this problem, we apply the kinetic energy formula;

        K.E  = \frac{1}{2} m v²  

m is the mass

v is the unknown

 Now, insert the parameters and solve;

        484  = \frac{1}{2} x 8 x v²

        484  = 4v²

           v² = 121

            v  = 11m/s

7 0
3 years ago
according to a rule-of-thumb, every 5 seconds, between a lightning flash and the following thunder gives the distance to the fla
jenyasd209 [6]
Given the speed of the sound in the problem which is 1 mile per 5 seconds. 

The speed is calculated by:

Speed = distance/time = (1mi/5s) (1610 m/1mi) = 300 m/s

Note that only 1 significant figure is given which is 5 second and so only 1 significant figure is justified in the result. The speed of sound is 343 m/s. therefore the rule of thumb is fairly close.
3 0
3 years ago
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