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Gre4nikov [31]
3 years ago
14

How the forces makes effect on the state of motion of an object ? Plz ans fast urgent

Physics
1 answer:
Ksju [112]3 years ago
6 0

Answer:

1. It may change the direction of an object in motion.

2. It may cause change in velocity of an object in motion.

Explanation:

1.It may change the direction of an object in motion.

When an object is in motion,an applied force on that object may change its direction.

For example, a sailboat moving eastward, can suddenly change its direction by interaction of a storm wind blowing form the south.

2. It may cause change in velocity of an object in motion .

A force applied to an object in motion can increase or decrease its speed. When the force is applied to the object in motion in the direction of that object, its velocity may increase.

On the other hand, when the force is applied in the opposite direction to the object in motion, its velocity may reduce.

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How much kinetic energy does a proton gain if it is accelerated, with no friction, through a potential difference of 1.00 V? The
ra1l [238]

Answer:

If energy is conserved, then the sum of the potential energy and the kinetic energy is a constant.

Assuming the proton starts from rest, so it's kineitc energy is zero, but it has a potential energy, PE equal to:

PE = qV

where q =1.6 x 10^-19 C

and V = 1.00 V

Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then:

PE* = 0,

KE* = 1/(2mv^2)

Now since

PE + KE = Total energy =PE* + KE*

Therefore,

qV + 0 = 0 + 1/2mv^2

Or

KE = qV = 1.6 10^-19 J

4 0
3 years ago
A bungee jumper who is about to jump has her energy stored entirely as
Morgarella [4.7K]

Answer:

it will get slower and eventually she will stop jumping because there isnt enough force on the gravity causing her to go up and down

Explanation:

!!

3 0
3 years ago
Calculate the GPE of a rock with a mass of 55kg on a cliff that is 27m high
GaryK [48]

Answer:

<em>P=mgh</em>

<em>P=mghm=55</em>

<em>P=mghm=55g=9.8 or ~10</em>

<em>P=mghm=55g=9.8 or ~10h=27</em>

Explanation:

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4 0
2 years ago
Consider another special case in which the inclined plane is vertical (θ=π/2). In this case, for what value of m1 would the acce
Lana71 [14]

Answer:

Explanation:

Consider another special case in which the inclined plane is vertical (θ=π/2). In this case, for what value of m1 would the acceleration of the two blocks be equal to zero

F - Force

T = Tension

m = mass

a = acceleration

g = gravitational force

Let the  given Normal on block 2 = N

and N = m_2 g \cos \theta

and the tension in the given string is said to be T = m_2 g \sin \theta

When the acceleration a=\frac{F}{m_1}

for the said block 1.

It will definite be zero only when Force is zero , F=0.

Here by Force, F

I refer net force on block 1.

Now we know

F = m_1g-T.

It is known that if the said

\theta=\frac{\pi}{2} ,

then Tension T= m_2g [since \sin(\pi/2) = 1],

Now making "F = m_1g - m_2g"

So If we are to make Force equal to zero

F=0 => m_1g = m_2g \ or \ m_1 = m_2

6 0
3 years ago
b) When the ball is near its maximum height it experiences a brief gust of wind that reduces its horizontal velocity by 2.50 m/s
fomenos

Answer:

The horizontal distance is 0.64 m.

Explanation:

Initial velocity, u =2.5m/s

The maximum horizontal distance is

R = \frac{u^2}{2g}\\\\R = \frac{2.5\times 2.5}{9.8}\\\\R = 0.64 m

3 0
3 years ago
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