Answer:
17.9 m/s
Step-by-step explanation:
Volume of the slick = 0.5 x π r² h--------------------------------- (1)
Where r = radius of slick
h = thickness of slick, 10⁻⁶m
If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)
V = 0.5 x π r² h
0.5= 0.5 x π x r² x 10⁻⁶
r² = 10⁶/ π
r = 10³/√π
dV/dt = πrh dr/dt + 0.5π r² dh/dt----------------------------------- (2)
Asumming the film thickness is constant , equation (2) becomes
dV/dt = πrh dr/dt-------------------------------- (3)
dV/dt = 0.1m³/day
r= 10³/√π
dr/dt= rate of expansion of the slick
Substituting into (3);
0.1 = π x 10³/√π x 10⁻⁶ x dr/dt
dr/dt = 0.1 x 10⁶/ ( π x 10³/√π)
= 17.9479 m/s
≅ 17.9 m/s
To make a frequency table, you will need to find the lowest and highest average number of movies.
Numbers go from 0.5 to 4.5.
And example of frequencies you could use are:
0-0.9 (1)
1-1.9(5)
2-2.9(5)
3-3.9(2)
4-4.9(1)
The frequencies are in parentheses beside the intervals.
Answer:
f(x) = 9(5/3)^x
Step-by-step explanation:
f(x) = a(b^x)
x = 0
9 = a(b⁰)
9 = a
f(x) = 9(b^x)
x = 1
15 = 9(b¹l
b = 15/9
b = 5/3
f(x) = 9(5/3)^x
Answer:
(a) 1, 2, 3, 6, 8
Step-by-step explanation:
Given
Required
The sequence of hours worked each day
<em>See attachment for options</em>
From the question, we understand that:
This means that, the middle number is 3 (when sorted)
So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively
Next, is to determine the mean of (a) and (d)
The mean of a data is calculated as:
So, we have:
(a)
(d)
Option (a) is true, because it has:
