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erastova [34]
3 years ago
7

Select all terms that apply to the shape

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0
Where the thing h buubbububuubub
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I need this ASAP!!! Giving brainliest
nignag [31]
Su = 15 !!!!!!!!!!!!!! chile i hope Im not wrong lol
7 0
3 years ago
Can any shape be a quadrilateral as long as it has 4 sides?
Effectus [21]
<h3>Answer: Yes</h3>

Explanation:

This is because

  • quad = 4
  • lateral = sides
5 0
3 years ago
Given: m∠AEB = 45° ∠AEC is a right angle. Prove: bisects ∠AEC. Proof: We are given that m∠AEB = 45° and ∠AEC is a right angle. T
NNADVOKAT [17]

Answer:

The proof is explained below.

Step-by-step explanation:

Given ∠AEB=45° and also ∠AEC is right angle i.e ∠AEC=90°

we have to prove that EB is the angle bisector.

In the right angled triangle AEC,

∠AEC=90° and also ∠AEB=45°

∵ ∠AEB+∠BEC=∠AEC

⇒ 45° + ∠BEC = 90°

By subtraction property of equality

∠BEC = 45°

Hence,  ∠AEB = ∠BEC = 45°

The angle ∠AEB equally divides by the line segment EB therefore, the line segment EB is the angle bisector of angle ∠AEB.

7 0
3 years ago
Read 2 more answers
A researcher is interested in determining the average number of years new teachers remain in the classroom. If past information
seraphim [82]
Answer: 385

Given: error: 6 months, standard deviation = 5 years is 60 months

Step 1: find the minimal sample size ‘n’ for 95% confidence interval

1-0.95= 0.05

0.05/2= 0.025

Step 2:
1-0.025= 0.975

View attachment for more steps

8 0
3 years ago
the angle of elevation from the bottom of a scenic gondola ride to the top of a mountain is 31 degrees. if the vertical distance
Eduardwww [97]

Answer:

The ride lasts 10 minutes.

Step-by-step explanation:

The triangle that is formed is attached.

In order to find out how long the ride lasts, we need to figure out the horizontal distance d.

From trigonometry we have:

tan(31^o)=\frac{902}{d}.

Therefore

d=\frac{902\:feet}{tan(31^o)}=1501\:feet.

Now the amount of time t the gondola ride lasts is equal to the distance d divided by the speed of the gondola:

t=\frac{1501ft}{155ft/sec} =\boxed{9.69\:minutes.}

To the nearest minute this is 10 minutes.

7 0
4 years ago
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