Answer:
The answer to this question is given below in the explanation section.
Explanation:
You can find a single number or name in a large worksheet containing thousands of numbers and names using the find and replacement feature in excel.
You can use Ctrl+F keyboard shortcut for finding and replacing features. When you press Ctrl+F, a dialog will get open, using this dialog, you can find the required number or name while entering in the search text box. Then, click on the Find button, if the worksheet matches the result, give you the matched result in the yellow highlighted color.
Also, you can use Ctrl+F to replace a name or number with some other name or number.
Alternatively, you can do this using the home tab, then find the option find and select under the editing group of commands.
Answer:
An elicitation technique is any of a number of data collection techniques used in anthropology, cognitive science, counseling, education, knowledge engineering, linguistics, management, philosophy, psychology, or other fields to gather knowledge or information from people.
Explanation:
This is configured on the BIOS Setup. During computer start-up usually for windows system this can be accessed via pressing on ESC or Function keys on immediate start up.
Answer:
Explanation:
#include <iostream>
using namespace std;
int main ()
{
int responses[30],count[6];
int score = 0;
string resp = " ";
for (int i = 0; i < 30; i++)
{
responses[i] = 0;
}
for (int i = 0; i < 6; i++)
{
count[i,1]=0;
count[i,2]=0;
count[i,0]=0;
}
while ((resp != "Y") && (resp != "y"))
{
for (int i = 0; i < 30; i++)
{
while ((score > 5) || (score < 1))
{
cout << "Student " << (i+1)<< " please enter a value (1-5):";
cin >> score;
}
responses[i] = score;
if((score > 5)||(score<1))
{
if(score==1) count[1]++;
if(score==2) count[2]++;
if(score==3) count[3]++;
if(score==4) count[4]++;
if(score==5) count[5]++;
}
score = 0;
}
cout<< "Response Frequency Percentage"<<endl;;
cout<< " 1 "<<count[1]<<" "<<(count[1]/30)<<"%"<<endl;
cout<< " 2 "<<count[2]<<" "<<(count[2]/30)<<"%"<<endl;
cout<< " 3 "<<count[3]<<" "<<(count[3]/30)<<"%"<<endl;
cout<< " 4 "<<count[4]<<" "<<(count[4]/30)<<"%"<<endl;
cout<< " 5 "<<count[5]<<" "<<(count[5]/30)<<"%"<<endl;
cout<< "Do you want to exit? Press Y to exit any other key to continue: ";
cin>> resp;
}
return 0;
}
Answer:
The correct loop is as follows:
for year in range(starting_tuitionYear, ending_tuitionYear, increment):
tuition = startingTuition + rate * startingTuition
startingTuition = tuition
print('Tuition for the year of ' + str(year)+ ' is ' + str(tuition));
Explanation:
Required
The correction to the attached program
Some variables are not needed; so, I've removed the redundant variables.
The main error in the program is in the loop;
After the tuition for each year has been calculated, the startTuition of the next year must be set to the current tuition
<em>See attachment for complete program</em>
