Ask question

Ask question

All categories

Montano1993 [528]

3 years ago

6

Help me please I need itt!!!!!!!

2 answers:

Firlakuza [10]3 years ago

8 0

4. This is simple the answer would be C. 60 because if you divide 9 by 1.50 you would get 6, so then you would need to multiply 6 by the number of erasers which is 10. So, 6 times 10 is 60.

5. This answer would be A. 1700 because (17 x 4) is 68 and 68 times 25 is 1700.

Hoped this helped!

Kruka [31]3 years ago

3 0

The answer is A because you need to multiply 17*4 frist then times it by 25.

You might be interested in

liraira [26]

Answer:

A is the answer you are looking for

4 0

3 years ago

use the coordinates of the vertex and the point to write the quadratic equation in standard form (-2, -2) point (-1, 1)

kogti [31]

Answer:

Step-by-step explanation:

vertex form of quadratic: y = a ( x − h ) ^ 2 + k

h= -2 , k = -2

y=a(x+2)^2-2

Substitute (-1,1)

1=a(-1+2)^2-2

a=3

y=3(x+2)^2-2

Expanding and give

y=3x^2+12x+10

5 0

3 years ago

Three friends Luke nick and serena are kicking a soccer ball to each other on the beach Luke kicks the ball to Serena who kicks

emmasim [6.3K]

Your answer is gonna be 2

3 0

2 years ago

Hamburger Heaven is having a lunch special where customers buy one 1/4-pound cheeseburger and get one free. If they set aside 10

omeli [17]

Answer: D
Explanation:
amount of meat = 104 pounds
No. Of burgers = 104 / 1/4
= 104 x 4/1 = 416

5 0

3 years ago

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

Part 2) The surface area of the pyramid is $288\ cm^{2}$

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

$sin(x)=\frac{16}{20}$

$x=arcsin(\frac{16}{20})=53.13\°$

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

so

$b=2h$

$sin(45\°)=\frac{h}{6\sqrt{2}}$

$h=6\sqrt{2}(sin(45\°))=6\ cm$

Find the value of b

$b=2(6)=12\ cm$

Find the surface area

$SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}$

3 0

3 years ago