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Pavel [41]
2 years ago
9

WHAT IS THIS QUESTION ASKING YOU TO FIND? Your bill at a restaurant is points

Mathematics
1 answer:
omeli [17]2 years ago
3 0

Answer:

33.06

Step-by-step explanation:

16% = 0.16

28.50 x 0.16 = 4.56

$28.50 + $4.56 = $33.06

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Is the prime factorization below correct?<br> 24 <br> 24+2.3.4<br> O Correct<br> Incorrect
xenn [34]
Is the prime factorization below correct

24
24+2.3.4



Answer: 100


Prime numbers are natural numbers (positive whole numbers that sometimes include 0 in certain definitions) that are greater than 1, that cannot be formed by multiplying two smaller numbers. An example of a prime number is 7, since it can only be formed by multiplying the numbers 1 and 7. Other examples include 2, 3, 5, 11, etc.
5 0
3 years ago
What is the missing length?
Kipish [7]

Answer:

80

Step-by-step explanation:

89^2-39^2=6400, 6400=80^2

4 0
3 years ago
Find a irrational number between 7.7 and 7.9 explain why it’s irrational
Alexeev081 [22]
7.77777777 repeating

Irrational numbers are:

Numbers that repeat 
7.7777777 repeats the number 7 after the decimal

Numbers that CANNOT be written as a simple fraction.
7.7777777 cannot be written as a fraction in simplest form.

Answer = 7.777777777 repeating

~Aamira~

Hope this helped :)
8 0
3 years ago
Read 2 more answers
Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th
grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

S = \{1,1,2,2,2,3\}

And the probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{6}

P(1) = \frac{1}{3}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{6}

P(2) = \frac{1}{2}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{6}

P(Odd Number) is then calculated as:

P(Odd\ Number) =  P(1) + P(3)

P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}

Take LCM

P(Odd\ Number) = \frac{2+1}{6}

P(Odd\ Number) = \frac{3}{6}

P(Odd\ Number) =  \frac{1}{2}

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

S = \{1,1,2,2,2,3,3\}

The probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{7}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{7}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{7}

P(Odd\ Number) = P(1) + P(3)

P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}

Take LCM

P(Odd\ Number) = \frac{2+1}{7}

P(Odd\ Number) = \frac{3}{7}

Comparing P(Odd Number) before and after

P(Odd\ Number) =  \frac{1}{2} --- Before

P(Odd\ Number) = \frac{3}{7} --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0
3 years ago
6. a) Rivka used the last four digits of her
bulgar [2K]

Answer: Her e-mail password is 1048222131

Step-by-step explanation:

You know that a part of Rivka's e-mail password is formed by the last four digits of her telephone number.

The exercise gives you the last four digits of Rivka's telephone number:

1048

Now, in order to find the other numbers, you need to descompose 1048 into its prime factors. Then:

1048=2*2*2*131

Therefore, based on this, you can determine that her e-mail password is:

e-mail\ password=1048222131

8 0
3 years ago
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