Answer:
a) Surface area = 616 cm²
b) Volume = V = 1083 cm³
Step-by-step explanation:
Surface area and volume of a regular triangular pyramid that has a base edge of 16 cm and a slant height of 15 cm
a) Formula for surface area = Base area × 1/2(perimeter × slant height)
Base area = Base edge²
=( 16 cm)² = 256 cm²
Perimeter = Base edge × 3
= 16 cm × 3 = 48 cm
Hence:
Surface Area = 256 cm² + 1/2(48 × 15)
= 256 cm² + 360 cm²
= 616 cm²
b) Volume = 1/3 × Base area × Height
1082.758616785cm³
Approximately = 1083 cm³
Answer:
---- At least 5 from marketing departments are extroverts
---- All from marketing departments are extroverts
---------- None from computer programmers are introverts
Step-by-step explanation:
See comment for complete question
The question is an illustration of binomial probability where


--- marketing personnel
--- proportion that are extroverts
Using the complement rule, we have:

So, we have:






So, we have:


Recall that:



--- approximated

--- marketing personnel
--- proportion that are extroverts
So, we have:





---------- computer programmers
--- proportion that are introverts
So, we have:




Answer: A: 1524 miles B: Average is 508 mph
Step-by-step explanation: Add the miles on the picture to get the total amount of miles traveled (1524) and then divide by 3 hours to get 508 mph.
Hope this helped!
Mark Brainliest if you want!
Answer:
A: 43.55
Step-by-step explanation:
Place value can be defined as the numerical value representing a digit owing to its position in a number. Some examples of the various place values used in representing each digit are tenths, hundredths, thousandths, unit, tens, hundreds, thousands etc.
For example, in the number 43.55;
- The place value of 4 is tens.
- The place value of 3 is units.
- The place value of 5 is tenths.
- The place value of 5 is hundredths.
Rounding up to the nearest tenth simply means to have 1 significant figure after the decimal point.
Therefore, 43.55 to the nearest tenth is 43.6
Answer: 21.6 m
Step-by-step explanation:
Given
A football field measures 
If a football field similar in shape to a full size has a length 
The ratio of the length of the original to the small field is the same
Assume the width of the small field is w
Thus, the width of the field is 21.6 m