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JulijaS [17]
2 years ago
12

Laquita practiced 60 math facts. Kinman practiced 15 more facts than Laquita. How many math facts did they practice in all?

Mathematics
1 answer:
Afina-wow [57]2 years ago
5 0

Answer:

They practiced a total of 75 math facts in all!

60 + 15 = 75 :D

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Find an equation of the line perpendicular to the graph of 14x-7=1 that passes through the point at (-2,4)
wolverine [178]

we know that

If two lines are perpendicular, then the product o their slopes is equal to minus one

so

m1*m2=-1

Step 1

<u>Find the slope of the given line</u>

we have

14x-7=1\\14x=1+7

x=8/14 -------> x=4/7

This line is parallel to the y-axis

so

the perpendicular will be parallel to the x-axis

Step 2

The equation of the line perpendicular to the given line is the y-coordinate of the given point

Point (-2,4)

the equation is

y=4

therefore

<u>the answer is</u>

y=4

see the attached figure to better understand the problem

5 0
3 years ago
In complete sentences explain how you would simplify √8/2.
Dovator [93]

Answer:

To find the square root of any number you must see what the number that you are trying to find the square of then you look at it and think what number times itself equals this number that you are trying to find the square root of the you solve it...

But in this case you have to divide 8 by 2 then find the square root of 4 which is 2

So there is your answer, Hope this helps:)

Step-by-step explanation:

Well, the answer is 2.

7 0
3 years ago
Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat
stiks02 [169]

Answer:

Part A

b. 14.6 ± 7.38

Part B

b. 3.43

Part C

a. P-value < 0.01

Part D

b. There is sufficient evidence to reject the null hypothesis

Step-by-step explanation:

Part A

The given data are;

The number of seedlings in the field = 20

The number of seedlings selected to receive herbicide A = 10

The number of seedlings selected to receive herbicide B = 10

The height in centimeters of seedlings treated with Herbicide A, \overline x _1 = 94.5 cm

The standard deviation, s₁ = 10 cm

The height in centimeters of seedlings treated with Herbicide B, \overline x _2 = 109.1 cm

The standard deviation, s₂ = 9 cm

The 90% confidence interval for μ₂ - μ₁, is given as follows;

\left (\bar{x}_{2}- \bar{x}_{1}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;

The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18

α = 100% - 90% = 10%

∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05

t_{(0.025, \, 18)} = 1.734

C.I. = \left (109.1- 94.5 \right )\pm 1.734 \times \sqrt{\dfrac{10^{2}}{10}+\dfrac{9^{2}}{10}}

C.I. ≈ 14.6 ± 7.37714603353

The 90% C.I. ≈ 14.6 ± 7.38

b. 14.6 ± 7.38

Part B

With the hypotheses are given as follows;

H₀; μ₂ - μ₁ = 0

Hₐ; μ₂ - μ₁ ≠ 0

The two sample t-statistic is given as follows;

t=\dfrac{(\bar{x}_{2}-\bar{x}_{1})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}+\dfrac{s _{2}^{2}}{n_{2}}}}

t-statistic=\dfrac{(109.1-94.5)}{\sqrt{\dfrac{10^{2} }{10}+\dfrac{9^{2}}{10}}} \approx 3.43173361147

The two sample t-statistic ≈ 3.43

b. 3.43

Part C

From the t-table, the p-value, we have, the p-value < 0.01

a. P-value < 0.01

Part D

Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis

b. There is sufficient evidence to reject the null hypothesis.

4 0
2 years ago
Which is the more reasonable measure for the length of a car?<br> 50m<br> 5cm<br> 5m<br><br> Thanks
Roman55 [17]

Answer:

5m

Step-by-step explanation:

8 0
2 years ago
Someone help me with this!
JulijaS [17]

Answer:

63

Step-by-step explanation:

you have to add

8 0
3 years ago
Read 2 more answers
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