All categories

3 years ago

How do you do this??????

Mathematics

2 answers:

slava [35]3 years ago

4 0

Answer:

2:1

Step-by-step explanation:

There are 14 spoons (not sure what they are) and 7 eyes so it is 14:7

simplified it is 2:1

Hope this helps :)

Anni [7]3 years ago

3 0

Answer:

Put a 1 where the eyeball icon is and put a 2 where the other symbol is (I’m not sure what it is supposed to be)

Step-by-step explanation:

I believe this is supposed to be the ratio 2:1

You might be interested in

Which of the following is equal to 10-5?

salantis [7]

Answer:

Step-by-step explanation:

$10^{-5}=\frac{1}{10^{5}}=\frac{1}{100000}=0.00001$

4 0

4 years ago

Read 2 more answers

What is (4+2) (-5) +3 (2+ -3 + 2

Mariulka [41]

(4+2)(−5)+3(2−3+2)
=(6)(−5)+3(2−3+2)
=−30+3(2−3+2)
=−30+3(−1+2)
=−30+(3)(1)
=−30+3
=−27
Hope this helps

5 0

3 years ago

Read 2 more answers

Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

Hence, (-1,5) is on the graph

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

(1,0) is not on the graph because g(x) is not equal to 0

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

Hence, $(3, \frac{1}{125})$ is on the graph

D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

Hence, $(-2, \frac{1}{25})$ is not on the graph

8 0

4 years ago

I want help its urgent!!! (iv), (v), (vi) Questions

Artist 52 [7]

Solution:

iv) Given equation: $x^{2} - y^{2} - 4x - 2y + 3$

Since we are given two variables, we need to split the original expression into two quadratic expressions as

$x^{2} - 4x + 4 - y^{2} - 2y - 1$

Factoring x first:

$x^{2} - 4x + 4 =$ $x^{2} - 2x - 2x + 4$

= $x (x - 2) - 2 (x-2)$

= $(x-2)(x-2)$

$= (x-2)^{2}$

Factoring y now:

$-y^{2} - 2y - 1 = -1(y^{2} + 2y + 1)$

= $-1(y^{2} + y + y + 1)$

= $-1[ y(y+1) + 1(y+1)]$

= $-1 [(y+1)(y+1)]$

= $(y+1)(-y-1)$

Therefore, the original expression becomes

$(x-2)^{2}+(y+1)(-y-1)\\or \\(x-2)(x-2) + (y+1)(-y-1)$

7 0

3 years ago

Billy is playing a board game. To win, Billy needs to spin a spinner (divided into four parts labeled 1, 2, 3, and 4) 2 times an

damaskus [11]

It is 6 yea yea yea yea yea

8 0

3 years ago

Read 2 more answers