Answer:
∠ ABC = 40°
Step-by-step explanation:
the 3 angles lie on a straight line ABE and sum to 180° , that is
50 - x + 80 + 2x + 40 = 180
x + 170 = 180 ( subtract 170 from both sides )
x = 10
Then
∠ ABC = 50 - x = 50 - 10 = 40°
Complete question :
Members of the swim team want to wash their hair. The bathroom has less than 5600 liters of water and at most 2.5 liters of shampoo. 70L+ 60S < 5600 represents the number of long-haired members L and short-haired members S who can wash their hair with less than 5600 liters of water. 0.02L + 0.01S < or equal to 2.5 represents the number of long-haired members and short-haired members who can wash their hair with at most 2.5 liters of shampoo. Does the bathroom have enough water and shampoo for 8 long-haired members and 7 short -haired members?
Answer:
Yes , there is enough water and shampoo
Step-by-step explanation:
Given that:
Number of long and short hair member who can wash their hair with less than 5600 litres of water.
70L+ 60S < 5600
Number of long and short hair member who can wash their hair with at most 2.5 litres of shampoo
0.02L + 0.01S ≤ 2.5
To check if bathroom has enough water and shampoo for 8 long haired and 7 short haired members.
Water check:
70L+ 60S < 5600
L = 8 ; S = 7
70(8) + 60(7) < 5600
560 + 420 < 5600
980 < 5600
Inequality constraint is satisfied ; There is enough water.
Shampoo check:
0.02L + 0.01S ≤ 2.5
L = 8 ; S = 7
0.02(8) + 0.01(7) ≤ 2.5
0.16 + 0.07 ≤ 2.5
0.23 ≤ 2.5
Inequality constraint is satisfied ; There is enough shampoo
Answer:
15
Step-by-step explanation:
The total number of teachers in the school is 100.
The number who teach Science is 60
The who teach humanities is 25.
The number that teach both humanities and Science is 15.
We want to find the number who teach Science but not Humanities.
We obtain this by subtracting the number of teachers who teach both subjects from the number that teach Science.
Therefore 25 teaches science but not Humanities
Answer:
f(2)=0
Step-by-step explanation:
You plug in 2 for any X's in the equation
f(2)=2^2-4
V = 1/3* h * r^3 pi
V ' = 1/3* h/3* (2r)^3 pi = h/9 * 8r^3 * pi
V ' / V = (h/9 * 8r^3 * pi) ÷ ( 1/3* h * r^3 pi ) = (8 * 3)/ 9 = 8 /3
