Write PQ−⇀− with P(2,−4) and Q(3,6) in component form.
1 answer:
Answer:
1,10
Step-by-step explanation:
The initial point of the vector is P(2,−4) and the terminal point of the vector is Q(3,6).
Subtract the coordinates of the initial point from the coordinates of the terminal point.
PQ−⇀−=<xQ−xP,yQ−yP>
Substitute the coordinates of the given points.
PQ−⇀−=<3−2,6−(−4)>
Simplify.
PQ−⇀−=<1,10>
Therefore, the component form of vector PQ−⇀− is <1,10>.
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