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mario62 [17]
2 years ago
9

3. Maxine has assets worth $145,000 and liabilities totaling $75,000. What is Maxine's net worth?

Mathematics
2 answers:
marshall27 [118]2 years ago
6 0
It would be C

145,000- 75,000=70000
BabaBlast [244]2 years ago
5 0
Answer: C.) $70,000

Explanation:
Assets - Liabilities = Net worth
$145,000 - $75,000 = $70,000
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Find the first 5 terms in the sequence an = 2n - 1
JulsSmile [24]

Answer:

1, 3, 5, 7, 9

Step-by-step explanation:

a_n = 2n - 1

n = 1:

a_1 = 2(1) - 1 = 2 - 1 = 1

n = 2:

a_2 = 2(2) - 1 = 4 - 1 = 3

n = 3:

a_3 = 2(3) - 1 = 6 - 1 = 5

n = 4:

a_4 = 2(4) - 1 = 8 - 1 = 7

n = 5:

a_5 = 2(5) - 1 = 10 - 1 = 9

Answer: 1, 3, 5, 7, 9

5 0
3 years ago
• karger's min cut algorithm in the class has probability at least 2/n2 of returning a min-cut. how many times do you have to re
MrRissso [65]
The Karger's algorithm relates to graph theory where G=(V,E)  is an undirected graph with |E| edges and |V| vertices.  The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs.  The algorithm is randomized and will, in some cases, give the minimum number of cuts.  The more number of trials, the higher probability that the minimum number of cuts will be obtained.

The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.

The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2),  which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.

This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.

We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.

Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n 

We will use a tool derived from calculus that 
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e   for x finite.  

Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e

Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]

P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n) 
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n

Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n)    [note: log(n) is natural log]
4 0
3 years ago
(b) What portion of the official U.S. poverty threshold (roughly $29,000 for a family of four) is met by the World Bank’s measur
otez555 [7]
World Bank's threshold for poverty is $1.25 per person per day. 
For a family of four this gives:
Daily income = (number of people) * threshold
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For a year this is:
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U.S. poverty threshold is set at $29000. Portion of threshold can be calculated as:
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The poverty threshold measured by World Bank is 6.29% of the U.S. poverty threshold.
5 0
3 years ago
Find the value of x in the diagram below
Marysya12 [62]

Answer:

120 degrees

Step-by-step explanation:

6 0
3 years ago
A cylinder has a radius of 10m and a 8m. What is the exact volume of the cylinder?
olasank [31]
The formula for the volume of a cylinder is πr^2*h. If you plug in the numbers of the radius and the height. π10^2*8=800π meters^3.
4 0
3 years ago
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