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Didn't know if this was a question but if yes it is
Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
Angle ABC is equal to 130.4°
Step-by-step explanation:
When an angle is bisected, it is divided into two equal parts, so if BD bisects ∠ABC, then the two angles that add up to it, ∠ABD and ∠DBC, must be equivalent.
We know that ∠ABD equals 65.2, so that must mean that ∠DBC also equals 65.2.
Here is our equation:
∠ABC=∠ABD+∠DBC
After substituting, we will get
∠ABC=65.2+65.2=130.4
130.4° is the measure of ∠ABC.
Answer:
The Volume of triangular prism
V = 450 cm³
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given The area of cross section of a prism A = 45cm²
and height (h) = 10 cm
The Volume of triangular prism
V = ( Base area X Height )
= 45 X 10
= 450 cm³
The Volume of triangular prism
V = 450 cm³
