Do you have a picture to your problem ?
Answer:
A
Step-by-step explanation:
Vertical angles are angles that are formed by 2 lines and are directly accross from each other. They do not share a ray, however they are always the same number of degrees.
so then the answer would be A, ∠ERT and ∠MRC since they are directly across from each other.
The Equation is y=+5
Why:
You want to find the equation for a line that passes through the point (-4,5) and has a slope of .
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was . So you can right away fill in the equation for a line somewhat to read:
y=x+b.
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(-4,5). When x of the line is -4, y of the line must be 5.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-4,5).
So, why not plug in for x the number -4 and for y the number 5? This will allow us to solve for b for the particular line that passes through the point you gave!.
(-4,5). y=mx+b or 5=0 × -4+b, or solving for b: b=5-(0)(-4). b=5.
Answer:
Li Ping's statement makes sense.
Step-by-step explanation:
The area of a square with side lengths a inches is given by, 
.
Now, the area of a parallelogram with equal sides a inches, which is not a square is given by, 
, where, h is the perpendicular distance between the opposite sides.
See the diagram attached.
Since a is the hypotenuse of as right triangle with height h, hence, a > h.
So, 
Therefore, Li Ping's statement makes sense. (Answer)
Answer:
Yp = t[Asin(2t) + Acos(2t)]
Yp = t²[At² + Bt + C]
Step-by-step explanation:
The term "multiplicity" means when a given equation has a root at a given point is the multiplicity of that root.
(a) r1=-2i; r2=2i g(t)=2sin(2t) + 3cos(2t)
As you can notice the multiplicity of this equation is 1 since the roots r1 = 2i and r2 = 2i appear for only once.
The form of a particular solution will be
Yp = t[Asin(2t) + Acos(2t)]
where t is for multiplicity 1
(b) r1=r2=0; r3=1 g(t)= t² +2t + 3
As you can notice the multiplicity of this equation is 2 since the roots r1 = r2 = 0 appears 2 times.
The form of a particular solution will be
Yp = t²[At² + Bt + C]
where t² is for multiplicity 2
