Answer:
Sally is not right
Step-by-step explanation:
Given the two sequences which have their respective 
terms as following:
Sequence A. 
Sequence B. 
As per Sally, there exists only one number which is in both the sequences.
To find:
Whether Sally is correct or not.
Solution:
For Sally to be correct, we need to put the terms of the respective sequences as equal and let us verify that.
When we talk about terms, 
here is a whole number not a fractional number.
But as per the statement as stated by Sally is a fractional number, only then the two sequences can have a number which is in the both sequences.
Therefore, no number can be in both the sequences A and B.
Hence, Sally is not right.
Answer
Multipy all of them
Step-by-step explanation:
mulitiply all of them
Answer:
the answer is d. 4x²+x-6
Step-by-step explanation:
In order to combine the fractions, they need to have the same denominator.
So, multiply each of their numerators by the denominator they need to be equivalent.
This would look like this:
3x/x+3 --> 3x(x)/x(x+3) ---simplify this as--> 3x²/x(x+3)
x-2/x --> (x-2)(x+3)/x(x+3) ---simplify this as --> x²+x - 6/x(x+3)
3x 3x(x) x-2 (x-2)(x+3)
----- ---> ----- and -------- ---> ---------
x+3 x(x+3) x x(x+3)
now that both fractions have the same denominator, we can add their numerators.
3x² + x²+x-6 = 4x²+x -6
This should now look like this:
4x²+x -6
-------------
x(x+3)
Answer:
32
Step-by-step explanation:
