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3 years ago

I need answers to these MCAS practice questions ASAP!

Mathematics

1 answer:

Semmy [17]3 years ago

8 0

I’ve attached a photo with my work ....
Hope it helps!!

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Please reply to my question I will surely mark u as brainly

pshichka [43]

Answer:

I might be wrong but I think the answered would be 14

Step-by-step explanation:

5+5=10+3=13+1=14

6 0

3 years ago

Find the values of P for which the quadratic equation 4x²+px+3=0?

klasskru [66]

<h3><u>Correct Questions :- </u></h3>

Find the values of P for which the quadratic equation 4x²+px+3=0 , provided that roots are equal or discriminant is zero .

<h3><u>Solution</u>:- </h3>

Let us Consider a quadratic equation αx² + βx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.

For equal roots

D = 0

$\quad\green{ \underline { \boxed{ \sf{Discriminant, D = β² - 4αc}}}}$

So,

$\sf{ β² - 4αc = 0}$

Here,

α = 4
β = p
c = 3

Now,

$\begin{gathered}\implies\quad \sf p²- 4 \times 4 \times 3 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²- 48 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²=48\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{48}\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{2 \times 2 \times 2 \times 2 \times 3} \end{gathered}$

$\begin{gathered}\implies\quad \sf p=± 2\times 2\sqrt{ 3 }\end{gathered}$

$\begin{gathered}\implies\quad \boxed{\sf{p=±4\sqrt{ 3 }}}\end{gathered}$

Thus, the values of P for which the quadratic equation 4x²+px+3=0 are-

4√3 and -4√3.

7 0

2 years ago

Jalil mixed 3/8 cup of sugar with 1 5/6 of water. How many more cups of water than sugar did he use in his mixture?

ValentinkaMS [17]

Answer:

2 and 3/4

Step-by-step explanation:

8 0

3 years ago

An equation of a parabola with its vertex at (-3,2) and focus at (-3,-1) written in general equation form

german

<span> we have that
standard form of equation for parabola:
(x-h)^2=-4p(y-k)
(h,k) --------->being the (x,y) coordinates of the vertex.
Parabola opens downwards because focus is below vertex on the axis of symmetry.
For given problem:
</span><span>vertex: (-3,2)
axis of symmetry: x=-3
p=distance from vertex to focus on the axis of symmetry=2-(-1)=3
4p=12
Directrix: y=2+p=5
Equation:
(x+3)^2=-12(y-2)

the answer is </span>(x+3)^2=-12(y-2)

5 0

3 years ago

Plz helpppppp me with this question

jarptica [38.1K]

Answer:

R L Q

Step-by-step explanation:

Im pretty sure thats right sorry if Its not

4 0

3 years ago

Read 2 more answers