If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer: 2 . 5
6 4
Step-by-step explanation:
Answer:
x = $20/day, y = $0.35/mile
Step-by-step explanation:
x = $/day, y = $/mile
4x + 160y = 136
1x + 240y = 104
You can solve by elimination or substitution.
By the isosceles triangle theorem the two angles opposite the equal sides are themselves equal while if the third side is different then the third angle is different.
Answer:
x=9
Step-by-step explanation:
Use the intersecting chord theorem:
RE*ET = UE*ES
Substitute values
21 (2x+2) = 30 (x+5)
Expand:
42x+42 = 30x + 150
transpose and simplify
42x-30x = 150 - 42
12x = 108
x = 9
