All categories

3 years ago

Find the value of X.

Mathematics

1 answer:

VashaNatasha [74]3 years ago

6 0

Answer:

19) 28°

20) 60°

21) 17°

Step-by-step explanation:

19)

Supplementary angles:

(x + 12)º + 140º = 180º

x + 12 + 140 = 180

x = 180 - 140 - 12

x = 28º

20)

Angles at a point:

(- 24 + x)° + 24° + 300° = 360°

- 24 + x + 24 + 300 = 360

x = 360 - 300

x = 60°

21)

Vertically opposite angles:

(1 + 3x)° = 52°

1 + 3x = 52

3x = 52 - 1

3x = 51

x = 17°

You might be interested in

Please help me out fast. And make sure to Write and solve an inequality. Or it isn't right.

fredd [130]

Answer:75x+160

8 is the answer exactly 8

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

CAN SOMEONE JUST PLEASE ANSWER THIS ASAP FOR BRAINLIEST!

nadezda [96]

The greatest common factor would be 14x^2 because 2 is the gretest power in common between the x variables and 14 is the greatest factor betwern the two leading coefficients. When factored using this greatest common factor this is the result:

$(14 {x}^{2} )(2 {x}^{3} + 1)$
I hope this helps!

8 0

3 years ago

PLS HELP ME ASAP WITH 1!

Vlad1618 [11]

All of these make use of the expansion
(a + b)² = a² + 2ab + b²
You would do well to memorize this "formula." Of course, it also helps to be able to double (or halve) a number, and to know the squares of small integers.

1.
x² +2x +1
x² -6x +9
x² +12x +36
x² -0.4x +0.04
4x² +28x +49
9x² +30x +25

2.
(x + 4)²
(x + 3)²
(x - 9)²
(x - 5)²

3. (12/2)² = 36

4. ±2√49 = ±14

3 0

3 years ago

The median of 6 numbers is 10, the mode is 8, the range is 8 and all numbers are even. Find the

BARSIC [14]

Answer:

√2

.................................................................

7 0

3 years ago

A = 4 0 0 1 3 0 −2 3 −1 Find the characteristic polynomial for the matrix A. (Write your answer in terms of λ.) Find the real ei

Illusion [34]

Answer:

Step-by-step explanation:

We are given the matrix

$A = \left[\begin{matrix}4&0&0 \\ 1&3&0 \\-2&3&-1 \end{matrix}\right]$

a) To find the characteristic polynomial we calculate $\text{det}(A-\lambda I)=0$ where I is the identity matrix of appropiate size. in this case the characteristic polynomial is

$\left|\begin{matrix}4-\lambda&0&0 \\ 1&3-\lambda&0 \\-2&3&-1-\lambda \end{matrix}\right|=0$

Since this matrix is upper triangular, its determinant is the multiplication of the diagonal entries, that is

$(4-\lambda)(3-\lambda)(-1-\lambda)=(\lambda-4)(\lambda-3)(\lambda+1)=0$

which is the characteristic polynomial of A.

b) To find the eigenvalues of A, we find the roots of the characteristic polynomials. In this case they are $\lambda=4,3,-1$

c) To find the base associated to the eigenvalue lambda, we replace the value of lambda in the expression $A-\lambda I$ and solve the system $(A-\lambda I)x =0$ by finding a base for its solution space. We will show this process for one value of lambda and give the solution for the other cases.

Consider $\lambda = 4$ . We get the matrix

$\left[\begin{matrix}0&0&0 \\ 1&-1&0 \\-2&3&-5 \end{matrix}\right]$

The second line gives us the equation x-y =0. Which implies that x=y. The third line gives us the equation -2x+3y-5z=0. Since x=y, it becomes y-5z =0. This implies that y = 5z. So, combining this equations, the solution of the homogeneus system is given by

$(x,y,z) = (5z,5z,z) = z(5,5,1)$

So, the base for this eigenspace is the vector (5,5,1).

If $\lambda = 3$ then the base is (0,4,3) and if $\lambda = -1$ then the base is (0,0,1)

3 0

3 years ago