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trapecia [35]
3 years ago
14

How do you do percent of change

Mathematics
2 answers:
amid [387]3 years ago
5 0

-- Find the amount of change.

           (new amount) - (old amount)

-- Divide it by the original amount.

-- Now you have the decimal amount of change.
   If you want the percentage, multiply the decimal by 100.
     (Move the decimal point 2 places that way ==>)

Whitepunk [10]3 years ago
4 0
Subtract the old from the new, then divide by the old value. Show that as a Percentage.
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X=2y-4 7x+5y=-66 solve by elimination
Alexxandr [17]

Answer:

{x,y}={-8,-2}

Step-by-step explanation:

 [1]    x = 2y - 4

Plug this in for variable  x  in equation [2]

  [2]    7•(2y-4) + 5y = -66

  [2]    19y = -38

Solve equation [2] for the variable  y

  [2]    19y = - 38

  [2]    y = - 2

By now we know this much :

   x = 2y-4

   y = -2

Use the  y  value to solve for  x

   x = 2(-2)-4 = -8

3 0
3 years ago
The explicit rule for the series 0, 1, 2, 3, ... is
Kobotan [32]

Answer:

Shyla's have not done any mistake.

Step-by-step explanation:

We have given that, The explicit rule for the series 0, 1, 2, 3, ... is given by a_n = n - 1.

Shyla's attempt to find the fifth  term in the sequence is shown below:

i.e. substitute n=5

a_5 = 5 - 1=4

Looking at the sequence, the 4th number  would be 3.

According to explicit rule the fourth term is

a_4 =4-1=3

Which is correct.

Similarly all the terms will get in this way.

So, Shyla's have not done any mistake.

7 0
3 years ago
Read 2 more answers
Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x2/(x4 +
ella [17]

Answer:

Given the function:  f(x) =\frac{x^2}{x^4+16}

A geometric series is of the form of :

\sum_{n=0}^{\infty} ar^n

Now, rewrite the given function in the form of \frac{a}{1-r} so that we can express the representation as a geometric series.

\frac{x^2}{x^4+16}

Now, divide numerator and denominator by x^4 we get;

\frac{\frac{1}{x^2}}{1+\frac{16}{x^4}} = \frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2}

Therefore, we now depend on the geometric series which is;

\frac{1}{1+x} =\sum_{n=0}^{\infty} (-1)^n x^n

let x \rightarrow x^2 then,

\frac{1}{1+x^2} =\sum_{n=0}^{\infty} (-1)^n x^{2n}

to get the power series let x \rightarrow \frac{4}{x^2}

so,

\frac{1}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}

Multiply both side by \frac{1}{x^2} we get;

\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\frac{1}{x^2} \cdot \sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}

or

\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =x^{-2} \cdot \sum_{n=0}^{\infty} (-1)^n (16)^n (x^{-2})^{2n}

or

\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n} \cdot x^{-2}

Using x^n \cdot x^m = x^{n+m}

we have,

\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}

therefore, the power series representation centered at x =0 for the given function is: \sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}







6 0
3 years ago
Megan has 30 brownies and 42 cupcakes to package. She wants to put the same numbers of brownies and cupcakes in each box. What i
valkas [14]
The answer would be 6
7 0
3 years ago
Please help I really don't get this I will give you 131 points that are all of them HELP ME SOON
zlopas [31]
The answer is 120 seconds.

Why?
180 divided by 4.5 is 40 seconds
200 divided by 2.5 is 80 seconds
Then add the seconds.
But I don’t understand how you walk so many meters in 180 seconds
4 0
3 years ago
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