Answer:
C. angle bisector
Step-by-step explanation:
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
Answer:
it is option 3
Step-by-step explanation:
-4(5p+3)
by opening brackets, you get
-20p -12
Answer:
91
Step-by-step explanation:
Todd’s average score for six tests = 92.
The sum of two of her test = 188
First, we need to find the total score for the six test. This given below:
Average = sum of all test / number of test
sum of all the test = average x number of test
average score for six tests = 92.
Number of test = 6
Sum of all the Tests = 92 x 6 = 552
Sum of four test = sum of all the test — sum of two test
Sum of four test = 552 — 188 = 364
Now we can solve for the average of the other four test as shown below:
Average of four test = 364/4= 91
The answer is: y= –1/3x–5
