Wet N' Dry camp provides water-based activities and ground sports activities for a
1 answer:
Answer:
- x+y≤80; x≥8; y≥5
- see attached for a graph
- Twenty campers are doing water-based activities and 40 campers are doing ground-based activities.
Step-by-step explanation:
1. Let x and y represent the numbers of campers doing water- and ground-based activities, respectively.
x + y ≤ 80 . . . . . . a maximum of 80 campers can be accommodated
x ≥ 8 . . . . . . . . . . a minimum of 8 campers should be water-based
y ≥ 5 . . . . . . . . . . a minimum of 5 campers should be ground-based
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2. See the attachment for a graph. Possible outcomes are shaded red. The boundary lines of the shaded area are included in the possible outcomes.
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3. Twenty campers are doing water-based activities and 40 campers are doing ground-based activities.
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m = the number of miles
30 + 0.18m ≤ 75
[They charge $30 plus $0.18 per mile(m), she can spend no more than $75. So $75 is the maximum/most she can spend, she can't spend over $75.]
Your answer is C
Now you need to find the solution of the inequality in order to graph it.
30 + 0.18m ≤ 75 Isolate "m". Subtract 30 on both sides
0.18m ≤ 45 Divide 0.18 on both sides
m ≤ 250 [this means that she can drive 250 miles on $75]
Next you need to graph it on a number line.
When the sign is ≤ or ≥, the dot is filled in
When the sign is < or >, the dot is an open circle/not filled in
m ≤ 250 [m is less than or equal to 250, so m can be 250 or any number less than 250]
The graph shows that she can only drive 250 miles or less on $75
