Answer:
x < 4
Step-by-step explanation:
3/4(x+8)>1/2(2x+10) (multiply both sides by 4)
(4)(3/4)(x+8)>(4)(1/2)(2x+10)
3(x+8)>2 (2x+10) (expand parentheses by distribution property)
x(3)+8(3)>(2x)(2)+10(2)
3x+24>4x+20 (subtract 3x from both sides)
3x+24 - 3x > 4x+20- 3x
24 > x+20 (subtract 20 from both sides)
24 - 20 > x + 20 - 20
4 > x (rearrange)
x < 4
Answer:
I know this is not exactly what your looking for but if you make a line and put all the points from 4+3i to 6-2i then you can find the distance between them.
Step-by-step explanation:
I'm so sorry that I don't really know the answer
Pls forgive me
Let's solve this problem step-by-step.
STEP-BY-STEP EXPLANATION:
Let's first establish that triangle BCD is a right-angle triangle.
Therefore, we can use Pythagoras theorem to find BC and solve this problem. Pythagoras theorem is displayed below:
a^2 + b^2 = c^2
Where c = hypotenus of right-angle triangle
Where a and c = other two sides of triangle
Now we can solve the problem by substituting the values from the problem into the Pythagoras theorem as displayed below:
Let a = BC
b = DC = 24
c = DB = 26
a^2 + b^2 = c^2
a^2 + 24^2 = 26^2
a^2 = 26^2 - 24^2
a = square root of ( 26^2 - 24^2 )
a = square root of ( 676 - 576 )
a = square root of ( 100 )
a = 10
Therefore, as a = BC, BC = 10.
If we want to check our answer, we can substitute the value of ( a ) from our answer in conjunction with the values given in the problem into the Pythagoras theorem. If the left-hand side is equivalent to the right-hand side, then the answer must be correct as displayed below:
a = BC = 10
b = DC = 24
c = DB = 26
a^2 + b^2 = c^2
10^2 + 24^2 = 26^2
100 + 576 = 676
676 = 676
FINAL ANSWER:
Therefore, BC is equivalent to 10.
Please mark as brainliest if you found this helpful! :)
Thank you and have a lovely day! <3
Answer:
The answer is just re look at the question A
Answer:
x = −3 and x = −2
Step-by-step explanation:
x^2 + 5x = −6
Add 6 to each side
x^2 + 5x+6 = −6+6
x^2 +5x+6 =0
Factor
What 2 number multiply to 6 and add to 5
3*2 =6
3+2 =5
(x+3)(x+2) =0
Using the zero product property
x+3 =0 x+2 =0
x+3-3=0-3 x+2-2=0-2
x=-3 x=-2
