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Ksivusya [100]
3 years ago
13

What is the value of y?

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0
Y= 54 degrees


explaination: triangle angles = 180 degrees
So
180-72(the angle you already have)
108 then divide by 2 because that is how many more angles you have and you get 54.
Nataly_w [17]3 years ago
5 0

Answer:

what is the bottom one

you can do

72+y + the bottom= 180

(sum of all angles of triangle is 180)

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Choose the equation that represents the line passing through the point (2. - 5) with a slope of -3.
inessss [21]

Answer:

Step-by-step explanation:

y + 5 = -3(x - 2)

y + 5 = -3x + 6

y = -3x + 1

Option 4 is the answer

8 0
3 years ago
Please help with steps as well!!
satela [25.4K]

Answer:x=24

Step-by-step explanation:x/2-8=4

Add 8 to both sides

x/2=12

Multiply each side by 2

x=24



3 0
3 years ago
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48 inches<br> 32 inches<br> 18. Inches <br><br><br> What is the area of the building front?
jarptica [38.1K]
48 inches is the area in the front of the building
7 0
2 years ago
Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which
alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L

1.25 liters of oil are needed.

6 0
2 years ago
Alma invests $300 in an account that compounds interest annually. After 2 years, the balance of the account is $329.49. To the n
-Dominant- [34]

Invested amount (P) = $300.

Time in years (t) = 2 years.

Balance after 2 years (A) = $329.49.

Let us assume rate of interest = r % compounds annually.

We know, formula for compound interest

A=P(1+r)^t

Plugging values in formula, we get

329.49=300(1+r)^2

\mathrm{Divide\:both\:sides\:by\:}300

\frac{300\left(1+r\right)^2}{300}=\frac{329.49}{300}

\left(1+r\right)^2=1.0983

Taking square root on both sides, we get

1+r=\sqrt{1.0983}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+r-1=\sqrt{1.0983}-1

r=\sqrt{1.0983}-1

r=1.048-1

r=0.048.

Converting it into percentage by multiplying by 100.

r=0.048 × 100

r  = 4.8 %

Therefore, the rate of interest on the account is 4.8% compounds annually.

5 0
3 years ago
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