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4 years ago

Evaluate 5-t/3 when t=12

Mathematics

2 answers:

Alecsey [184]4 years ago

5 0

Answer:

1 is your answer

Step-by-step explanation:

Remember to follow PEMDAS.

First, plug in 12 for t

5 - (12/3)

Divide

5 - (4)

Simplify. Subtract

5 - 4 = 1

1 is your answer

~Senpai

slega [8]4 years ago

3 0

Answer:

The value of the provided expression when t=12 is 1.

Step-by-step explanation:

Consider the provided expression.

$5-\frac{t}{3}$

We need to solve the expression when t=12.

Substitute the values of t in the provided expression.

$5-\frac{12}{3}$

Simplify the expression.

$5-4$

$1$

Hence, the value of the provided expression when t=12 is 1.

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A rectangular storage container with an open top is to have a volume of 10 m3 . then length of its base is twice the width. mate

katrin [286]

Answer:

The cost of materials for the cheapest such container is $163.54.

Step-by-step explanation:

A rectangular storage container with an open top is to have a volume of 10 m³.

The volume of the rectangle is

$\text{Volume} =\text{Length} \times \text{Width} \times \text{Height}$

Length of its base is twice the width.

Let Width be 'w'.

Length is l=2w.

Height be 'h'.

$10 =2w\times w\times h$

$10=2w^2h$

The height in terms of width is represented as,

$h=\frac{10}{2w^2}$

$h=\frac{5}{w^2}$

According to question,

The cost is 10 times the area of the base and 6 times the total area of the sides.

i.e. Cost is given by,

$C=10(L\times W)+6(2\times L\times H+2\times W\times H)$

$C=10(2w\times w)+6(2\times 2w\times \frac{5}{w^2}+2\times w\times \frac{5}{w^2})$

$C=20w^2+\frac{120}{w}+\frac{60}{w}$

$C(w)=20w^2+\frac{180}{w}$

To get the minimum value,

Differentiate the cost w.r.t 'w',

$C'(w)=20\frac{d(w^2)}{dw}+180\frac{d(w^{-1})}{dw}$

$C'(w)=20\times 2w-180 w^{-2}$

$C'(w)=40w-\frac{180}{w^2}$

To find critical points put derivate =0,

$40w-\frac{180}{w^2}=0$

$40w=\frac{180}{w^2}$

$w^3=\frac{180}{40}$

$w=\sqrt[3]{4.5}$

$w=1.65$

We find the second derivative to minimize,

$C''(w)=40\frac{d(w)}{dw}-180\frac{d(w^{-2})}{dw}$

$C''(w)=40+360(w^{-3})$

$C''(w)>0$

As $C''(w)>0$ it is the minimum cost.

The cost is minimum at w=1.65.

Substitute the values in the cost function,

$C(1.65)=20(1.65)^2+\frac{180}{1.65}$

$C(1.65)=54.45+109.09$

$C(1.65)=163.54$

Therefore, the cost of materials for the cheapest such container is $163.54.

7 0

4 years ago

Find a formula for the inverse of the function. f(x) = e^6x − 9

STatiana [176]

Answer:

$f^{-1}(x)=\frac{1}{6}\ln(x+9)$

Step-by-step explanation:

So we have the function:

$f(x)=e^{6x}-9$

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

$x=e^{6f^{-1}(x)}-9$

Add 9 to both sides:

$x+9=e^{6f^{-1}(x)}$

Take the natural log of both sides:

$\ln(x+9)=\ln(e^{6f^{-1}(x)})$

The right side cancels:

$\ln(x+9)=6f^{-1}(x)$

Divide both sides by 6:

$f^{-1}(x)=\frac{1}{6}\ln(x+9)$

And we're done!

7 0

3 years ago

Explain why a graph that fails the vertical-line test does not represent a function. Be sure to use the definition of a function

ArbitrLikvidat [17]

Explanation:

A function is a relationship where any one x-value/input only has one corresponding y-value/output. (note: a y-value can have multiple x-values).

> This can be called "assigning one y-value to every x element".

The vertical line test places a line that would connect all y-values of an x-value (that is, if it were to have multiple y-values). If multiple points can be found along the vertical line, it is, therefore, by the definition of a function, not a function. (Because an x-value will have more than one y-value).

So, a graph that fails the vertical-line test does not represent a function because an x-value will correspond with more than one y-value.

hope this helps!!

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2 years ago

4.7% of the 6540000 indiana residents were listen foreign born in 2012, how many people in indiana were foreign born?

umka2103 [35]

Answer:

The answer would be 307,380 people.

Step-by-step explanation:

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3 years ago

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