Answer:
£10.71
Step-by-step explanation:
Given the original price including discount od shorts = £15
Percent discount = 40%
Original price = x
Using the expression to calculate x
x + (40%of x) = 15
x +0.4x = 15
1.4x = 15
x = 15/1.4
x = £10.71
Hence the non sale price is £10.71
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Start by using trig to find the length of the line LJ
The triangle KJL (big right angled triangle) has been given the following dimensions
Hypotenuse =

The adjacent angle is 30 degrees
Since we have the hypotenuse and the angle we must use the equation
opposite = Sin(angle) x Hypotenuse
Opposite= sin30 x

Opposite=

Therefore line LJ is

Now look at the smaller right angled triangle (LMJ)
Hypotenuse is the line LJ which is

The adjacent angle is 45
Since we have hypotenuse and angle we must use the equation opposite = sin(angle) * h
therefore
x=

* sin45= 4
Since we need your monthly bill we will call it the variable B for now, (Unless you have the bill, if so replace it with the variable)
Multiply 1.64 x B since the exchange rate is different than the US bill,
For example, say your bill is $100 in the U.S.
You do 1.64 x 100 = A monthly bill of $164 if you lived in Britain
Answer:
x=5
y=4
Step-by-step explanation:
Step 1:
Let us solve for <em>x</em> using the
equation by <u>isolating terms containing the variable</u>:

Great! <em>x</em> is 5... let's find <em>y</em>.
Step 2:
Since we know the value of <em>x</em>, we can use what we know to find <em>y</em> using the <u>other equation</u>:

<em>Given that x=5, we can </em><u><em>replace</em></u><em> x with 5</em>.

<em>I hope this helps! Let me know if you have any questions :)</em>