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vova2212 [387]
3 years ago
9

An angle less than 90 degrees ​

Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

<u>Acute Angle</u>

Step-by-step explanation:

<u>Obtuse Angle</u> is greater than 90 degrees

<u>Right Angle</u> is exactly 90 degrees

<u>Acute Angle</u> is less than 90 degrees

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Chad had 30 dollars to spend on 3 gifts. He spent 9 dollars on gift A and 6
myrzilka [38]

Answer:

Chad had 15 dollars left for gift C.

Step-by-step explanation:

Given:

Chad had total amount = 30 dollars.

Amount spend on gift A = 9 dollars.

Amount spend on gift B = 6 dollars.

To Find:

Amount Left for gift C = ?

Solution:

Total Amount = 30 dollars.

Total number of gifts = 3 i .e Gift A, Gift B , Gift C.

Total amount spend for  Gift A and Gift B = Amount spend on gift A + Amount spend on gift B

∴ Total amount spend for  Gift A and Gift B = 9 + 6

∴ Total amount spend for  Gift A and Gift B = 15 dollars.

Now,

Amount Left for Gift C = Total Amount - Total amount spend for  Gift A and Gift B.

∴ Amount Left for Gift C = 30 - 15

∴ Amount Left for Gift C =  15 dollars

5 0
3 years ago
Channing jogs 10 miles a week. How many miles will she jogot in 52 weeks?
Alborosie
It might me this.. 10 * 52 = 520 
6 0
3 years ago
What fraction of 3 liters is 800 ml?
Alex
Reduced it will be 3/4 your welcome ":)

7 0
3 years ago
Read 2 more answers
9 + 10? <br><br>I'm 5 years old idk what I'm using buh fu
just olya [345]
The answer is 19. Hopefully this helps 

5 0
3 years ago
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The hypotenuse of a right triangle is 24 ft. long. the length of one leg is 44 ft. more than the other. find the lengths of the
Mekhanik [1.2K]
The way to solve the missing side of a right triangle is normally by the Pythagorean Theorem:
{a}^{2}  +  {b}^{2}  =  {c}^{2} \\  {a}^{2}  =  {c}^{2}  -  {b}^{2}  \:  \infty  \: \sqrt{ {a}^{2} }  = \sqrt{( {c}^{2}  -  {b}^{2}) } \\ a= \sqrt{( {c}^{2}  -  {b}^{2}) }
where c always is the hypotenuse
So c = 24 ft
b = 44 + a
{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\  {a}^{2}  +  {(a + 44)}^{2}  =  {24}^{2}  \\  {a}^{2}  +  {a}^{2}  + 88a + 1936 = 576
Now combine like terms:
2{a}^{2}  + 88a + 1936 = 576 \\  2{a}^{2}  + 88a + 1936 - 576 = 0 \\ 2{a}^{2}  + 88a + 1360 = 0
Now we have to try to factor this quadratic equation, first let's take out 2:
2({a}^{2}  + 44a + 680) = 0
we need factors of 680 whose sum = 44
20×34, 10×68, 17×40
however... 20+34=54, 10+68=78, 17+40=57
So we will need to use the quadratic equation unfortunately :(
x = ( - b +  -  \sqrt{( {b}^{2}  - 4ac)}) \div 2a
Now the "x" is actually our "a", the a is 1, b is 44, c is 680
a = ( - 44 +  -  \sqrt{( {44}^{2}  - 4(1)680)})  \\ \div  \: 2(1) \\  a = ( - b +  -  \sqrt{(1936 - 2720)}) \\  \div  \: 2
a = ( - 44 +  -  \sqrt{(-784)}) \\  \div  \: 2  =  - 44 \div 2 \:  +  - (i \sqrt{784}) \div 2 \\ a =  - 22 +  - i \sqrt{16}  \sqrt{49}  \div 2 \\
a =  - 22 +  - 28i \div 2  \\ a =  - 22 +  - 14i
not quite sure where to go from these imaginary numbers...
I DON'T THINK A RIGHT TRIANGLE WITH THOSE DIMENSIONS IS POSSIBLE







8 0
3 years ago
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