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3 years ago

ODD BALL OUT

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Answer:

Step-by-step explanation:

15 is not a prime number, but it is composite.

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Manipulate the triangle so angle A measures 41° and

Sergio039 [100]

Answer: angle B will be 90°

Sum of the angles = 180°

4 0

3 years ago

Read 2 more answers

A city currently has 125 streetlights. As part of a urban renewal program, the city council has decided to install 2 additional

SVEN [57.7K]

Answer:

213

Step-by-step explanation:

if you multiply 44 weeks by 2 streetlights per week you get 88 streetlights which you then add to the lights you already have.

3 0

3 years ago

What is the slope intercept form of the equation of the line?

beks73 [17]

Answer:

The slope-intercept form of the equation of the line is:

y = 2/3x + 2

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

m is the slope

b is the y-intercept

Given the points

(0, 2)

(3, 4)

(x₁, y₁) = (0, 2)

(x₂, y₂) = (3, 4)

Using the formula

Slope = m = [y₂ - y₁] / [x₂ - x₁]

= [4 - 2] / [3 - 0]

= 2 / 3

Thus, the slope of the line = m = 2/3

We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

From the graph, it is clear

at x = 0, y = 2

Thus, the y-intercept b = 2

now substituting m = 2/3 and b = 2 in the slope-intercept form

y = mx+b

y = 2/3x + 2

Therefore, the slope-intercept form of the equation of the line is:

y = 2/3x + 2

5 0

3 years ago

An aluminum can is a right cylinder. Find the amount of paper needed for the can's label and the total

Rina8888 [55]

Answer:

Label: About 527.9 square centimeters

Aluminum: About 835.7 square centimeters

Step-by-step explanation:

Amount of paper needed for the label:

You can imagine taking off the label and unrolling it, forming a rectangle. The height of this rectangle will be the height of the cylinder, while the length of the rectangle will be the circumference of the cylinder. Therefore, the area of that rectangle will be $2\pi r h= 2 \cdot \pi \cdot 7 \cdot 12\approx 527.9$ .

Amount of aluminum needed for the can:

This time, you need to add in the top and bottom of the can as well, which each have area $\pi r^2$ . Together, they have area $2\pi r^2=2\cdot \pi \cdot 7^2\approx 307.9$ . Adding this to the area of the sides, you get a total of about 835.7 square centimeters.