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Step2247 [10]
3 years ago
15

A prime number p is a divisor of 420 and 540. How many possible values of p are there?

Mathematics
2 answers:
kotykmax [81]3 years ago
7 0

Answer:

3 possible prime divisors that go into 420 and 540:

2,3,5

hope this helps!

Step-by-step explanation:

Andrew [12]3 years ago
3 0

Answer:

3 prime divisors that go into 420 and 540 are-

2,3,5

hope this helps!

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Step-by-step explanation:

For the limit of a function to exist, then the right hand limit of the function must be equal to its left hand limit as shown;

If the function is f(x), for f(x) to exist then;

\lim_{n \to a^{+} } f(x) =  \lim_{n \to a^{-} } f(x) =  \lim_{n \to a } f(x)

Given the function;

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Lets check if the above statement is true.

The right hand limit of the function occurs at x> 9

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The left hand limit occurs at x<9

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From the above calculation, it can be seen that \lim_{x \to 9^{+} } f(x) \neq   \lim_{x \to 9^{-} } f(x), this shows that the function given does not exist at the given point.

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