|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|
|PQ| = 3y; |PR| = 42; |QR|=?
subtitute
42 = 2(3y)
6y = 42 |divide both sides by 6
y = 7
|QR| = 3(7) = 21
Subtract 8d from both sides
21 = 12d + 5 - 8d
Simplify 12d + 5 - 8d to 4d + 5
21 = 4d + 5
Subtract 5 from both sides
21 - 5 = 4d
Simplify 21 - 5 to 16
16 = 4d
Divide both side by 4
16/4 = d
Simplify 16/4 to 4
4 = d
Switch sides
d = 4
<u>Check answer</u>
8d + 21 =12d + 5
Let d = 4
8 × 4 + 21 = 12 × 4 + 5
Simplify 8 × 4 to 32
32 + 21 = 12 × 4 + 5
Simplify 12 × 4 to 48
32 + 21 = 48 + 5
Simplify 32 + 21 to 53
53 = 48 + 5
Simplify 48 + 5 to 53
53 = 53
Answer:
Step-by-step explanation:
The linear equation that is perpendicular to the line x+3y=21 is:
y = 3*x - 6
<h3>How to find the equation of the line?</h3>
A general line in the slope-intercept form is written as:
y = m*x + b
Where m is the slope and b is the y-intercept.
Two linear equations are perpendicular if the product between the two slopes is equal to -1.
Rewriting the given line we can get:
x +3y = 21
3y = 21 - x
y = 21/3 - x/3
y = (-1/3)*x + 21/3
Then the slope is (-1/3), if our line is perpendicular to this one, then:
m*(-1/3) = -1
m = 3
our line is:
y = 3*x + b
To find the value of b, we use the fact that our line passes through (1, - 3)
-3 = 3*1 + b
-3 - 3 = b
-6 = b
The line is y = 3*x - 6
Learn more about linear equations:
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A) $7. 69 change she will get back when she use 50.00 for her pants and sweater
