A. 4 . . . Yes. 52/4 = 13
b. 26 . . . Yes. 52/26 = 2
<em>c. 3 . . . . No. 52/3 = 17 and 1/3</em>
d). 13 . . Yes. 52/13 = 4
44
Step-by-step explanation:
let boys be x and girls be y
x/y=5/6
x=5y/6....(1)
if 6 boys join the club that will be x+6
Therefore:
(x+6)/y=13/12
13y=12x+72
13y-12x=72
Recall x=5y/6
Therefore:
13y-12(5y/6)=72
13y-(2*5y)=72
13y-10y=72
3y=72
y=24 people
Therefore:
x=(5*24)/6
x=20 people
Therefore people in the club before are 20+24=44
Answer:

Step-by-step explanation:
To solve this problem, first you have to use the order of operations stands for parenthesis, exponents, multiply, divide, add, and subtract from left to right. Remember to use the order of operations stands for "Please Excuse My Dear Aunt Sally."
Do parenthesis first.


Next, exponent.


Multiply & divide numbers from left to right.

Finally, add & subtract numbers from left to right.

As a result, the correct answer is 21.
Answer:
Step-by-step explanation:
In propositional logic and Boolean algebra, De Morgan's laws are a pair of transformation rules that are both valid rules of inference. ... The rules allow the expression of conjunctions and disjunctions purely in terms of each other via negation.