Answer:
2kx+4y=20 ⇒ kx+2y=10
3x+6y=30 ⇒ x+2y= 10
k is the coefficient of x, so it is the slope of the line
- when k=1, both equations will be same, then there are many solutions
- when k=0 there is one solution
- when k is anything different, then the lines will be parallel, so no solutions
Y=mx+b
6x+2y=-88
2y=-88-6x
y=-44-3x
y=-3x-44
m is the slope
b is the y-intercept
I think it would be 137.1, due to the total being 360. Just subtract.
When x=2 y = 110 which means when when x=1 y = 55
the graph would be 11*55 or 605
The table would be 280/4= 70 70*11=770
Which means the difference is 770-605=165
165 is ur answer
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
