I'm not sure by the way you layed out the question but, 2. 5(14-23)+8/2. First you have to use distributive method so 5 times 14 equals 70 and 5 times 23 equals 115 so that means it's 70-115+8/2. Then 8/2 equals 4 so 70-115+4 so then 70-115 equals negative 35. That is -35+4 so the answer is -31 or in other words negative thirty one.
I am not sure if I helped out but I tried my best
<span>The answer is 0.00001267 m = 1.267 * 10^(-5) m. In scientific notation, the number is written as two factors - a number m from 0-10 and 10 raised to the n power: m x 10^n. 0.00001267 m = 1.267 x 0.00001 m. 0.00001 m = (0.1)^5 = 10^(-5). So: 0.00001267 m = 1.267 x 0.00001 m = 1.267 x (0.1)^5 m = 1.267 x 10^(-5) m.</span>
The answer is 3/20 I believe
Answer:
![x \cdot y=1](https://tex.z-dn.net/?f=x%20%5Ccdot%20y%3D1)
Step-by-step explanation:
![(7^x)^y = 7](https://tex.z-dn.net/?f=%287%5Ex%29%5Ey%20%3D%207)
Apply exponent rule
:
![\implies7^{xy}=7^1](https://tex.z-dn.net/?f=%5Cimplies7%5E%7Bxy%7D%3D7%5E1)
![\implies x \cdot y=1](https://tex.z-dn.net/?f=%5Cimplies%20x%20%5Ccdot%20y%3D1)
Possible values for x and y: ![x=\dfrac12 \ \ \ \ \ y=2](https://tex.z-dn.net/?f=x%3D%5Cdfrac12%20%5C%20%5C%20%5C%20%5C%20%5C%20%20y%3D2)
Answer:
![K = C + 273.15](https://tex.z-dn.net/?f=K%20%3D%20C%20%2B%20273.15)
Step-by-step explanation:
We are given the following in the question:
"A temperature in kelvin is 273.15 greater than the temperature in degrees Celsius."
We have to write an equation that relates temperature K in Kelvin to temperature C in Celsius.
According to the given relation, we can write the equation:
![K = C + 273.15](https://tex.z-dn.net/?f=K%20%3D%20C%20%2B%20273.15)
is the required equation that provides a relation between temperature in Kelvin and temperature i Celsius.