Answer:
Step-by-step explanation:
f(x) = 3x + 1 and g(x) = x^2 - 6
(f + g) (x)
(3x + 1) + (x^2 - 6)
3x + 1 + x^2 - 6
3x - 5 - x^2
=> -x^2 + 3x - 5
I hope this helps!
You just put the numbers on the number line and count the integers between them.
However, the formula for difference = (big number) - (small number)
Therefore,
41 - (-23)
= 41 + 23
= 64
So the difference is 64.
d/dx √x/√(x + 1)
= d/dx √[x/(x + 1)]
= d/dx [x/(x + 1)]^(1/2)
= (1/2)[x/(x + 1)]^(- 1/2)
= (1/2)[x/(x + 1)]^(- 1/2) * (x + 1)^(-2)
Explanation:
√a/√b = √(a/b)
√x = x^(1/2)
Chain rule:
d/dx f(g(... w(x))) = f’(g(... w(x))) * g’(... w(x)) * ... * w’(x)
Quotient rule:
d/dx f(x)/g(x) = [f’(x)g(x) - g’(x)f(x)]/[g(x)]^2