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gulaghasi [49]
3 years ago
14

What are two or more substances not chemically combined called? *

Chemistry
2 answers:
V125BC [204]3 years ago
8 0

Answer:

✖︎ Mixture←  is the right answer answer, so don't choose that....…

THE corrects answer would be MIXTURE

!!!!!!Brainliest??

EXPLANATION

✰1.  I take the quiz

✰2. The word already describe it self, mixture is a substance made by mixing other substances together.

✰a mixture is a material made up of two or more different substances which are physically combined. A mixture is the physical combination of two or more substances in which the identities are retained and are mixed in the form of solutions, suspensions and colloids.

Harman [31]3 years ago
5 0
Answer is mixture!!
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How many grams of oxygen are required to burn 13.5 g of acetylene
Vinil7 [7]

Answer:

41.54 grams of oxygen are required to burn 13.5 g of acetylene

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₂H₂: 2 moles
  • O₂: 5 moles
  • CO₂: 4 moles
  • H₂O: 2 moles

Being the molar mass of the compounds:

  • C₂H₂: 26 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₂H₂: 2 moles* 26 g/mole= 52 grams
  • O₂: 5 moles* 32 g/mole= 160 grams
  • CO₂: 4 moles* 44 g/mole= 176 grams
  • H₂O: 2 moles* 18 g/mole= 36 grams

You can apply the following rule of three: if by stoichiometry 52 grams of acetylene react with 160 grams of oxygen, 13.5 grams of acetylene react with how much mass of oxygen?

mass of oxygen=\frac{13.5 grams of acetylene*160 grams of oxygen}{52 grams of acetylene}

mass of oxygen= 41.54 grams

<u><em>41.54 grams of oxygen are required to burn 13.5 g of acetylene</em></u>

<u><em></em></u>

8 0
3 years ago
Question (a).....................
Rudiy27
I dont get the question ???
6 0
3 years ago
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