What is the new freezing point if you put in 100.O g of sodium chloride into 750. mL of water?
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<h3>Answer:</h3>
1257.45 L
<h3>Explanation:</h3>We are given;
- Initial volume of Helium gas, V1 as 806 L
- Initial temperature of Helium gas,T1 as 20.9°C
- Initial pressure of Helium gas, P1 as 753 mmHg
- Pressure of Helium at the altitude 6.8 km, P2 as 417 mmHg
- Temperature of Helium gas at the altitude 6.8 Km, T2 as -19.1°C
But, K = °C + 273.15
Therefore, T1 = 294.05 K and T2 = 254.05 K
- We are required to calculate the new volume of the balloon at 6.8 km.
- To determine the new volume we are going to use the combined gas law.
- According to the combined gas law,
Thus, rearranging the formula;
Therefore, the volume of the balloon at an altitude of 6.8 km is 1257.45 L