Answer:
Step-by-step explanation:
Divide both sides by 1/3, which is equivalent to mulitplying by 3
x - 10 = -12
Add 10 to both sides
x = -2
Answer:
7/5 or 1.4 batches
Step-by-step explanation:
batches Sugar used
1 10
x 14
cross multiply
10x=14
x=14/10
x=1.4 or 7/5
Answer:
Step-by-step explanation:
![\displaystyle \frac{3\sqrt{3}}{2}a^2 = A \hookrightarrow \frac{3\sqrt{3}}{2}6^2 = A \\ \frac{3\sqrt{3}}{2}[36] = A; 54\sqrt{3}\:[or\:93,530743609...] \\ \\ \boxed{93,5 \approx A}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7Da%5E2%20%3D%20A%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D6%5E2%20%3D%20A%20%5C%5C%20%5Cfrac%7B3%5Csqrt%7B3%7D%7D%7B2%7D%5B36%5D%20%3D%20A%3B%2054%5Csqrt%7B3%7D%5C%3A%5Bor%5C%3A93%2C530743609...%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B93%2C5%20%5Capprox%20A%7D)
I am joyous to assist you at any time.
To find the maximum velocity you have to differentiate the function respect to r.
v = k(R - r)r^2 = kRr^2 - krr^2 = kRr^2 - kr^3
k and R are constants.
=> v' = 2kRr - 3kr^2 = kr(2R - 3r)
maximum velocity => v' = 0 => kr(2R - 3r) = 0
r = 0 or 2R - 3r = 0 => r = 2R / 3
Answer: r = 2R / 3
