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2 years ago

Yes hbc7)7/67), Z a mf s

Mathematics

2 answers:

Masja [62]2 years ago

6 0

Answer:

What is your question supposed to be? It's just a bunch of gibberish.

dexar [7]2 years ago

4 0

Answer:

Um wht I understood half of wht u said lol

Step-by-step explanation:

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Aaron is making a jewelry box of wood in the shape of a rectangular prism the jewelry box will have the dimensions shown in the

Natali [406]

Answer:

b. $342

Step-by-step explanation:

Base = Length * width

Base Area = 12 * 5

B = 180 square inches.

Perimeter of the prism will be :

P = 2 (length) + 2 (15)

P = 2 * 12 + 30

P = 54 inches

Height of the jewelry container will be :

X = Ph + 2B

X = 54 * 6 + 2 * 180

X = 684 square inches.

Total cost for paint of jewelry box is :

X * cost per inch

Total cost = 682 * $0.50

Total Cost = $342.

8 0

2 years ago

Round your answer to the nearest hundredth.

Natali5045456 [20]

Answer:

uh, I think it's 4.13

Step-by-step explanation:

5*sin(65)=4.13 now this seems a bit off but this was the only one that actually worked

5 0

1 year ago

Which sequence follows the rule 2n + 6, where n represents the position of a term in a sequence? 6, 8, 12, 18, . . . 6, 12, 18,

melamori03 [73]

ANSWER

8, 10, 12, 14, . . .

EXPLANATION

The given rule for the sequence is :

f(n)=2n+6

The domain for a sequence is the set of natural numbers.

When n=1,

f(1)=2(1)+6=8

When n=2,

f(2)=2(2)+6=10

When n=3,

f(3)=2(3)+6=12

When n=4,

f(4)=2(4)+6=14

Therefore the sequence that follows the given rule is

8, 10, 12, 14, . . .

8 0

2 years ago

Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le

Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes =68

$Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}$

$68= \frac{\text{Sum of all lengths}}{7}$

$68 \times 7 =\text{a+b+c+d+e+f+g}$

$476=\text{a+b+c+d+e+f+g}$ --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

$476=x+x+x+84+84+84+4x+14$

$476=7x+266$

$\frac{476-266}{7}=x$

$30=x$

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0

2 years ago

WILL GIVE BRAINLIEST<br> Subtract 9x^2+7x-2<br> from 8x-10

konstantin123 [22]

Answer:

x − 9 x ^2 − 8

Step-by-step explanation:

6 0

2 years ago