1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kupik [55]
3 years ago
5

2x-y=4 -2x+y=7 is there a solution

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

\text{Given : 2x - y = 4 and x + 2y = 7}

\text{Solution : according to the question here we are provided with} \\ \text{two equations separately. So, let's name them as eq(1) and eq(2).} \\  \text{ The rest is followed as we continue to get to our goal}  \\  \\  \sf  {1}^{st}  \: equation  : \\   \quad\dashrightarrow \frak{2x - y = 4} \\  \\ \quad \dashrightarrow \frak{ \red{x =  \frac{y + 4}{2} }} \qquad  \sf ...eq(1) \\  \rm{ now \:  \: as \:per \: our \: plan \: we \: need \: to \: get \: eq(2) } \\  \\  \sf{ {2}^{nd}   \:equation} : \\   \quad\dashrightarrow \frak{ x + 2y = 7} \\  \\ \quad\dashrightarrow \frak{ \red{y =  \frac{7 - x}{2}}} \qquad \sf ...eq(2) \\  \\  \text{Now, finding x and y}  \\  \\  \underline{ \frak{Finding  \: x}}\\  \\  \quad \hookrightarrow \frak{x =  \frac{y  +  4}{2}}  \\  \\ \quad \hookrightarrow \frak{2x =  \frac{7 - x}{2} + 4} \\  \\ \quad \hookrightarrow \frak{2x =  \frac{7 - x + 8}{2}} \\  \\ \quad \hookrightarrow \frak{2x =  \frac{1 - x}{2}} \\  \\\quad \hookrightarrow \frak{4x =  1 - x}  \\  \\ \quad \hookrightarrow \frak{5x = 1}  \\  \\\quad \star \qquad \underline{ \boxed{ \green{ \frak{x =  \frac{1}{5}}}}} \\  \\  \underline{ \frak{Finding \:  y}} \\  \\  \quad \hookrightarrow \frak{y =  \frac{7 - x}{2}} \\  \\ \hookrightarrow \frak{2y =  7 -  \frac{1}{5} } \\  \\ \hookrightarrow \frak{2y =   \frac{35 - 1}{5} } \\  \\ \hookrightarrow \frak{2y =  \frac{34}{5}} \\  \\ \hookrightarrow \frak{y =   \frac{34}{5}  \times \frac{1}{2}} \\  \\ \hookrightarrow \frak{y =   \frac{17}{5} } \\  \\ \star \qquad \underline{ \boxed{ \frak{ \green{y = 3 \frac{2}{5}  }}}}

astra-53 [7]3 years ago
4 0
There is one solution which is: x= 3/2, y= 10. Or as in ordered pairs (3/2,10)
You might be interested in
Help please asap!!!!
NISA [10]

Answer:

invalid conclusion

Step-by-step explanation:

5 0
3 years ago
Complete the table below for the function y = -6x + 4.
liraira [26]
When x= -5, y= 34; when y= 64, x = -10
4 0
3 years ago
Help! will give points for brainliest
Misha Larkins [42]

Answer:

27

Step-by-step explanation:

Choose two outputs that are 3 values apart and find their ratio:

... f(3)/f(0) = 216/8 = 27

6 0
3 years ago
Choose the correct response ​
Aliun [14]

Answer:

74 hope this works if not I'm sorry

6 0
3 years ago
I need help quick thanks!!!
aliya0001 [1]

Answer:

x = 1.5

Step-by-step explanation:

-1.2 (3 - x) = -1.8

<em>Apply distributive property</em>

-3.6 + 1.2x = -1.8

<em>Get 1.2x alone so add -3.6 to each side</em>

1.2x = 1.8

<em>Get x alone so divide 1.2 on each side</em>

x = 1.5

Hope this helps!

4 0
3 years ago
Other questions:
  • you bought 4 bananas and 5 apples at the store for $2.50 the next day you bought 10 bananas and 3 apples at the store for $3.40.
    10·1 answer
  • 15 decreased by twice a number x in algebriac expression
    15·1 answer
  • The lines shown below are perpendicular. If the green line has a slope of
    10·2 answers
  • What is the value of m?
    9·2 answers
  • A team spent 20 mins on passing drills and 40 minuets ona shooting drill, what is the ratio of time spent on shooting drills to
    13·1 answer
  • Walter makes a cable
    11·1 answer
  • What is the common ratio of the sequence?<br> -2, 6, -18, 54....<br> -3<br> -2<br> 3<br> 8
    6·2 answers
  • Kawai requires a loan of $33,000 to buy a used sport utility vehicle. His banks offers financing at 6.75% compounded monthly, fo
    8·1 answer
  • Graph the equations f(x)=-1/9x-3<br> g(x)=5/9x-9
    5·1 answer
  • Someone pls help I need this like now pls lots of points and brainliest
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!