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nikitadnepr [17]
3 years ago
5

If .19 moles of sodium carbonate are dissolved in enough water to make .400 L of solution, what is the molarity?

Chemistry
1 answer:
ANEK [815]3 years ago
5 0

Answer:

=0.475M

Explanation:

Molarity=(moles of solute))/(litres of solution)

So, molarity in this question:

=(0.19 moles of sodium carbonate)/(0.4 L of solution)

=0.475M

~Hope this helps:)

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Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.
valina [46]

Answer: The amount of heat energy in joules required to raise the temperature is 526 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m= mass of substance = 7.40 g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 29.0°C

Final temperature of the water = T_f  = 46.0°C

Change in temperature ,\Delta T=T_f-T_i=(46.0-29.0)^0C=17.0^0C

Putting in the values, we get:

Q=7.40g\times 4.184J/g^0C\times 17.0^0C

Q=526J

The amount of heat energy in joules required to raise the temperature is 526 Joules

4 0
3 years ago
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7nadin3 [17]

Answer:

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Explanation:

4 0
3 years ago
How many moles of ions are in 1.45 mol of K2SO4 ?
leonid [27]

Answer:

Explanation:

First we look generally at what makes K2SO4.

In one mole of K2SO4, there are 2 moles of the potassium ion (K+) and 1 mole of sulfate ion (SO4 2-).

Knowing that; in 1.75 moles of K2SO4, there must be 2 x 1.75moles of potassium ion (K+) and 1 x 1.75moles of Sulfate ion (SO4 2-)

This gives us 3.5moles of K+ and 1.75moles of SO4 2-

3 0
4 years ago
For the complete combustion of 47 g of gasoline (octane, C8H18) , the mass of oxygen consumed is
aleksklad [387]

Answer: d) 164.9 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}     \text{Moles of octane}=\frac{47g}{114g/mol}=0.412moles

The balanced chemical reaction is:

2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)  

According to stoichiometry :

2 moles of C_8H_{18} require = 25  moles of O_2

Thus 0.412 moles of C_8H_{18} will require=\frac{25}{2}\times 0.412=5.15moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=5.15moles\times 32g/mol=164.9g

Thus 164.9 g of oxygen is consumed.

4 0
3 years ago
Henri Becquerel and the Curies found out that _____.
evablogger [386]
<span>Atoms were not indivisible and indestructible.</span>
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4 years ago
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