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3 years ago

A sample of phosphonitrilic chloride, PNCl2, contains 0.170 mol of the compound. What is the mass of the sample, in grams?

Chemistry

1 answer:

Galina-37 [17]3 years ago

5 0

Answer: 19.7 grams PNCl2

Explanation: To find the mass of the sample in grams, all you have to do is convert. You need to multiply 0.170 mol by the unit multiplier 115.89 grams PNC12 (molecular mass - rounded) / 1 mol PNC12. This will cancel out the moles of PNCl2, leaving you with grams as the units. Now, all you have to do is multiply. 0.170*115.89 = 19.7 grams PNCl2 (rounded, again).

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How could measuring the melting point of a solid help decide whether it was a mixture or a compound?

mars1129 [50]

Answer: It can't.

Explanation:

In most cases, the melting point alone will not enable you to identify a compound. Millions of solid organic compounds, and their melting points, are known. Perhaps 10,000 of these will have the same melting point as your unknown compound.

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3 years ago

Temperature is ____ related to the average kinetic energy of a gas.

Nastasia [14]

Answer:

directly

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3 years ago

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Take car traveling with constant speed travels at 150 km in 7200 a. what is the speed of the car?

Andrej [43]

<span>Find the speed of the car in which it travels at 150 km in 7200 seconds.
This is an easy question, you just need to follow the given formula as always.
Since the time and the distance is already given, we are now looking for the speed
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</span>

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3 years ago

What is the name and molecular formula of the gas formed when baking soda was combined with vinegar, which you identified using

sammy [17]

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3 years ago

Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge

zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

To know more about Empirical Formula

brainly.com/question/14044066

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2 years ago