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klemol [59]
2 years ago
8

WILL GIVE BRAINLIEST

Mathematics
2 answers:
Dovator [93]2 years ago
4 0

Answer:

V=πr²h

V=(3.14)(15cm)²(325cm)

V=229,613 cm³

masha68 [24]2 years ago
3 0

Answer:

d

Step-by-step explanation:

trust me i used online calculator and got that exact answer

pls make me brainliest :)

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How much longer is 18.25 centimeters than 75.4 milimeters
Amanda [17]

Answer:

10.71

Step-by-step explanation:

You first convert 75.4 millimeters to centimeters, and you will get 7.54. Now you subtract 18.25 and 7.54 to get the answer 10.71

4 0
2 years ago
The perimeter of a rectangle is 132 feet and its area is 1080 square feet. find the dimensions
FrozenT [24]
2x + 2y=132

xy=1080

Let x=1080/y

2160/y + 2y=132
2y^2 - 132y +2160=0
2(y^2-66y+1080)=0
2(y-30)(y-33)=0
y=30 or y=33
(36,30) or (30,36)

So... x=30,36 and y=36,30. Either way, the answer is 30 by 36 or 36 by 30. 
5 0
3 years ago
What is the value of x ? round your answer to the nearest tenth .
djverab [1.8K]

Answer:

39 maybe i don't know

Step-by-step explanation:

4 0
3 years ago
There are 26 third graders and 32 fourth graders going on a field trip. Each van can carry 10 people
nataly862011 [7]

Answer:

Approximately 6 buses

Step-by-step explanation:

If you are wanting know how many vans they are going to need:

26 + 32                    -This helps you know how many total kids there are

= 58

58 / 10                      -This solves how many buses you'll need

= 5.8                   - Round up, and say you need 6 buses.


4 0
3 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
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