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34kurt
3 years ago
5

The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero

to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds
Mathematics
1 answer:
mario62 [17]3 years ago
8 0

Answer:

289

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

(1)

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(2)

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DiKsa [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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