Answer:
- Elanor's standardized score is 1.19
- Gerald's standardized score is 0.72
- Elanor has higher score
Step-by-step explanation:
To compare Elanor's and Gerald's math scores, we need to standardize them and calculate their z-scores.
z score can be calculated using the formula
z=
where
- M is the mean score of the exam
- s is the standard deviation of the exam
Elanor's standardized score is:
z(e) = 
≈ 1.19
Gerald's standardized score is:
z(g)= 
≈ 0.72
Since z(e) > z(g), Elanor has higher score
Answer:
(2 1) for L (4 3) for G (4 -1)
Step-by-step explanation:
Since 15 workers did 8 hours of work, the total amount of work needed is 120 hours. Half of this job would be 60 hours. Then divide this amount by the 5 workers doing the job. This would make the job 12 hours
Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Answer:
using quaderatic expression solving problems of algebraic expressions.
Step-by-step explanation:
no1.
take the smallest side to be x
and the longest side to be x-1/3
then expand the expression equating to 30.
then solve for x value
