There is a typo error in the last part of the question. The corrected part is-
"If the probability that she orders just a grilled cheese sandwich is .76, what is the probability that she will order a grilled cheese or fries?"
Answer:
The probability that she will order a grilled cheese sandwich or fries is <u>0.43.</u>
Step-by-step explanation:
Given:
Probability of ordering fries is, 
Probability of ordering cheese sandwich is, 
Probability of ordering both sandwich and fries is, 
Probability of ordering cheese sandwich or fries is given by the union of both the events 'F' and 'S' given as 
.
Now, using addition theorem of probability, we get:
Therefore, probability of ordering cheese sandwich or fries is 0.43.
If Monica walks
1km...........................15min
?km............................60min
60/15=4
Monica walks 4km in 60 min(1H)
1km=1,000m
4km=4,000m in 1 hour
Here's a scenario that you can edit to your own advantage. You own a shirt shop. Each shirt sells for 15 dollars, and to make profit annually you need to sell $62,365 worth of shirts. If you've sold 2,000 shirts so far, how many shirts do you need to meet your quota. How many shirts on average per month would you have to sell?
Answer:
E. -0.723
Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.
Step-by-step explanation:
Information provided
represent the sample mean for the length
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level
t would represent the statistic
represent the p value for the test
System of hypothesis
We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
since we don't know the population deviation the statistic is:
(1)
Replacing in formula (1) we got:
E. -0.723
P value
The degrees of freedom are given by:
Since is a two tailed test the p value would be:
Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.
First, we need to get the total number students by adding the number of men and women. 63 + 86 = 149. This is the total number of samples. To get the probability that a randomly selected is a woman, we can write the ratio as 63:149 or the probability is 63/149.
