I think ur problem is missing something bc I got this
The answer is
8x^4-10x^3-3x^2
Assuming this is the equation you want to operate on:



Before final operation we have to assume that x is not equal to 0. :)
We want to solve the equation :

first, multiply both sides by 4:


divide both sides by 3:

add -3 to both sides:

Answer: x=9
Answer:
Step-by-step explanation: