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mixer [17]
3 years ago
14

Find the future value of the principal.help me pls :(​

Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

54,000

Step-by-step explanation:

30,000/8% then multiply the answer by 10 than add that to 30,000

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Please help and show your work, will mark brainliest
Alja [10]

Answer:

y = -2x + 9              y =1/9x + 4/9

Step-by-step explanation:

-9/2 = -x -1/2y

-1/2y = x - 9/2

y = -2x + 9

-4 - x = -9y

-9y = -4 - x

y = 1/9x + 4/9

8 0
2 years ago
I have to write the following expression in simplest form 7p-1-9p+5
g100num [7]
The simplest way of writing this: 
<span><span><span><span>7p</span>−1</span>−<span>9p</span></span>+5</span><span>=<span><span><span><span><span><span>7p</span>+</span>−1</span>+</span>−<span>9p</span></span>+5</span></span>Combine Like Terms:<span>=<span><span><span><span>7p</span>+<span>−1</span></span>+<span>−<span>9p</span></span></span>+5</span></span><span>=<span><span>(<span><span>7p</span>+<span>−<span>9p</span></span></span>)</span>+<span>(<span><span>−1</span>+5</span>)</span></span></span><span>=<span><span>−<span>2p</span></span>+4</span></span>Answer:<span>=<span><span>−<span>2p</span></span>+<span>4</span></span></span>
8 0
3 years ago
N the sequence generated by the formula an = n – 4, which term has a value of 8?
Mrrafil [7]

Answer:

The twelfth term :)

hope this helps

6 0
3 years ago
Read 2 more answers
20,884 divided by 92​
Alenkasestr [34]

20884/92 math problems division = 227. Therefore 227 to 2 decimal places= 227

7 0
2 years ago
Read 2 more answers
An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
2 years ago
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