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3 years ago

Simplify by Distributing and then Combining Like Terms (C.L.T.): 4(2m+5n)−3(m−7n)

Mathematics

1 answer:

MaRussiya [10]3 years ago

5 0

Answer:

5m+41n

Step-by-step explanation:

4(2m+5n)-3(m-7n)

8m+20n-3m+21n

8m-3m+20n+21n

5m+20n+21n

5m+41n

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a cuboid with a volume of 924 cm3 has dimensions 4cm (x+1)cm and (x+11)cm. show clearly that x^2 +12x-220=0. show the equation b

nikdorinn [45]

Answer:

Part 1)

The equation by factorization is

$x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))$

Both values of x are

$x1=-6+\sqrt{266}$

$x2=-6-\sqrt{266}$

Part 2) The dimensions of the cuboid are

$4\ cm$ , $(-5+\sqrt{266})\ cm$ and $(5+\sqrt{266})\ cm$

Step-by-step explanation:

step 1

we know that

The volume of the cuboid is equal to

$V=LWH$

substitute the given values

$V=4(x+1)(x+11)$

$V=924\ cm^{3}$

$4(x+1)(x+11)=924\\4(x^{2}+11x+x+11)=924\\ 4(x^{2}+12x+11)=924\\x^{2}+12x+11=231\\x^{2}+12x-230=0$

Complete the square

$x^{2}+12x-230=0$

$x^{2}+12x=230$

$x^{2}+12x+36=230+36$

$(x+6)^{2}=266$

square root both sides

$x+6=(+/-)\sqrt{266}$

$x=-6(+/-)\sqrt{266}$

$x1=-6+\sqrt{266}$

$x2=-6-\sqrt{266}$

therefore

The equation by factorization is

$x^{2}+12x-230=(x-(-6+\sqrt{266}))(x-(-6-\sqrt{266}))$

step 2

Find the dimensions of the cuboid

The dimensions are

$4\ cm$

$(x+1)\ cm -----> (-6+\sqrt{266}+1)=(-5+\sqrt{266})\ cm$

$(x+11)\ cm ----> (-6+\sqrt{266}+11)=(5+\sqrt{266})\ cm$

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