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Liula [17]
3 years ago
9

The radius of a circle is 9 times the radius of a smaller circle. The area of the smaller circle is 50 square centimeters. What

is the area of the larger circle?
Mathematics
2 answers:
scoundrel [369]3 years ago
4 0

Answer:

Let R = radius of big circle

r=radius of small circle

A1=Area of small circle

A2=Area of big circle

R=9r

A1=50cm^2

A1=pi*r*2

A2=pi*R^2

A2=pi*(9r)^2

A2=81*pi*r^2

A2=81*A1

A2=4050cm^2

Hence the big circle has area of 4050cm^2

Step-by-step explanation:

Strike441 [17]3 years ago
4 0

Answer:

4050 on edge 100%

Step-by-step explanation:

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Semenov [28]

Answer:

The answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

Step-by-step explanation:

Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.

First, let's begin with 2:

\frac{2}{5} = \frac{2}{5}

\frac{2}{8} = \frac{1}{4}

\frac{2}{20} = \frac{1}{10}

Then, let's do 5:

\frac{5}{2} = \frac{5}{2}

\frac{5}{8} = \frac{5}{8}

\frac{5}{20} = \frac{1}{4}

Note that we already have \frac{1}{4}, so we do not need to include an additional one.

Now, let us do 8:

\frac{8}{2} = \frac{4}{1}

\frac{8}{5} = \frac{8}{5}

\frac{8}{20} = \frac{2}{5}

See how we already have \frac{2}{5}, so we won't have to include that as well.

Finally, let's do 20:

\frac{20}{2} = \frac{10}{1}

\frac{20}{5} = \frac{4}{1}

\frac{20}{8} = \frac{5}{2}

Now see that we already have both \frac{4}{1} and \frac{5}{2}, so we won't have to include both of them, as they are both extras.

Hence, the answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
8 0
3 years ago
Read 2 more answers
help with this please
Ierofanga [76]

Answer:

see explanation

Step-by-step explanation:

Under a translation < 5, - 9 >

5 is added to the original x- coordinate and 9 is subtracted from the original y- coordinate, that is

A(1, 4 ) → A'(1 + 5, 4 - 9 ) → A'(6, - 5 )

B(2, - 2 ) → B'(2 + 5, - 2 - 9 ) → B'(7, - 11 )

C(- 3, 2 ) → C'(- 3 + 5, 2 - 9 ) → C'(2, - 7 )

7 0
3 years ago
How can I do number 25?
Delicious77 [7]
+
^ that's your answer

3 0
3 years ago
Read 2 more answers
Only do 7. iii<br>I will mark you as brainliest.. I don't have time please fasttt​
Sophie [7]

Answer:

Check my explanation

Step-by-step explanation:

(i) the area of the floor is 30m² (6m · 5m)

(ii) the perimeter of the floor is 22m (6m + 5m + 6m + 5m)

(iii) the area of the walls is:

     24m² (for the 6m by 4m walls)

     20m² (for the 5m by 4m walls)

     88m² in total total

7 0
3 years ago
3sina-4sin4a/sin5a<br> if a=-45 degree
Ierofanga [76]

Given:

The given expression is:

\dfrac{3\sin a-4\sin 4a}{\sin 5a}

To find:

The value of the given expression at a=-45.

Solution:

We have,

\dfrac{3\sin a-4\sin 4a}{\sin 5a}

Substituting a=-45, we get

\dfrac{3\sin (-45)-4\sin [4(-45)]}{\sin [5(-45)]}

=\dfrac{-3\sin (45)+4\sin (180)}{-\sin (225)}

=\dfrac{-3\sin (45)+4\sin (180)}{-\sin (180+45)}

=\dfrac{-3\sin (45)+4\sin (180)}{\sin (45)}

On substituting \sin (180), we get,

=\dfrac{-3\sin (45)+4(0)}{\sin (45)}

=\dfrac{-3\sin (45)+0}{\sin (45)}

=\dfrac{-3\sin (45)}{\sin (45)}

=-3

Therefore, the value of the given expression at  a=-45 is -3.

8 0
2 years ago
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