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Liula [17]
3 years ago
9

The radius of a circle is 9 times the radius of a smaller circle. The area of the smaller circle is 50 square centimeters. What

is the area of the larger circle?
Mathematics
2 answers:
scoundrel [369]3 years ago
4 0

Answer:

Let R = radius of big circle

r=radius of small circle

A1=Area of small circle

A2=Area of big circle

R=9r

A1=50cm^2

A1=pi*r*2

A2=pi*R^2

A2=pi*(9r)^2

A2=81*pi*r^2

A2=81*A1

A2=4050cm^2

Hence the big circle has area of 4050cm^2

Step-by-step explanation:

Strike441 [17]3 years ago
4 0

Answer:

4050 on edge 100%

Step-by-step explanation:

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Since segment AC bisects (aka cuts in half) angle A, this means the two angles CAB and CAD are the same measure. I'll refer to this later as "fact 1".

Triangles ABC and ADC have the shared segment AC between them. By the reflexive property AC = AC. Any segment is equal in length to itself. I'll call this "fact 2" later on.

Similar to fact 1, we have angle ACB = angle ACD. This is because AC bisects angle BCD into two smaller equal halves. I'll call this fact 3

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To summarize so far, we have these three facts

  1. angle CAB = angle CAD
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in this exact order, we can use the ASA (angle side angle) congruence property to prove the two triangles are congruent. Facts 1 and 3 refer to the "A" parts of "ASA", while fact 2 refers to the "S" of "ASA". The order matters. Notice how the side is between the angles in question.

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Once we prove the triangles are congruent, we use CPCTC (corresponding parts of congruent triangles are congruent) to conclude that AB = AD and BC = BD. These pair of sides correspond, so they must be congruent in order for the entire triangles to be congruent overall.

It's like saying you had 2 identical houses, so the front doors must be the same. The houses are the triangles (the larger structure) and the door is an analogy to the sides (which are pieces of the larger structure).

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Step-by-step explanation:

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